CODEWITHSUNDEEP
arraysmatlab
Larisa
Larisa

Reputation: 791

Accept an array with n elements and return them as an array - Matlab

I would like to write a function that accepts an array of any number of values and returns their changed values in a new array.

function zArray = y(xArray)
    zArray = [];
    for x = 1:size(xArray,2)
        if x >= -2 && x < -1
            z = ln(x + 2);
        elseif x >= -1 && x < 0
            z = (x + 1).^2;
        elseif x >= 0 && x <= 2
            z = (x + 1)/(x.^2 + 1);
        else 
            z = -10
        end
        zArray(end + 1) = z;
    end
end

I then call the function with:

[z1, z2, z3] = y([0, 1, -1])

Which gives me the following output and message:

z1 =

    1.00000    0.60000  -10.00000

error: element number 2 undefined in return list

I am new to Matlab and am not sure how Matlab for loops and arrays work. If I understand correctly, I am not adding the changed values correctly to the array which is supposed to hold output values and therefore can not read them in this manner, but if I am not mistaken, array(end + 1) = z is appending the element z to the end of the array.

Am I making more than one mistake? Please point out any of them because I have troubles understanding the Matlab syntax, even though I do know how to program in some other languages.

Upvotes: 0

Views: 52

Answers (1)

Bhoke
Bhoke

Reputation: 521

I think you desire the following thing but you are confused with syntax: 

function zArray = y(xArray)
zArray = zeros(size(xArray));

for x = 1:size(xArray,2)
    xVal = xArray(x);
    if xVal >= -2 && xVal < -1
        zArray(x) = log(xVal + 2);
    elseif xVal >= -1 && xVal < 0
        zArray(x) = (xVal + 1).^2;
    elseif xVal >= 0 && xVal <= 2
        zArray(x) = (xVal + 1)/(xVal.^2 + 1);
    else
        zArray(x) = -10;
    end
end
end

Upvotes: 1

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