CODEWITHSUNDEEP
pythoncallbackreturn
Alexander
Alexander

Reputation: 971

function returns previous value

I want to get the users input as a number, check its validity and return it. If the number is invalid, I wish to repeat the input process. However if I type:

  1. "5b"
  2. "50.4"

The function doesn't return 50.4. Instead it returns 5.0, as the remainder of the first function call is executed. How can I fix the above issue, to only get 50.4?

def inputGoal ():
    goalFiltered = ""
    print ('1: ' + str(goalFiltered))
    goal = input("Input number: ")

    for char in goal:
        matched = False
        for sign in comparator:
            if (sign == char):
                matched = True
                if (char != ','):
                    goalFiltered += sign
                elif (char == ','):
                    goalFiltered += '.'
        if (matched == False):
            print ("Please repeat input, valid characters are: 0 1 2 3 4 5 6 7 8 9 , .")
            inputGoal()
            #return
    goalFiltered = float(goalFiltered)
    return (goalFiltered)

The comparator variable is:

comparator = ['0','1','2','3','4','5','6','7','8','9',',','.']

Upvotes: 0

Views: 811

Answers (1)

user7111497
user7111497

Reputation:

If I understood your problem correctly, I think you can just do this:

while True:
    ask = input("Input the number:\t") #The \t just puts a tab so it looks nice
    if ask == float(ask):
        break
    else:
        print("The number is incorrect. Try again.")
        continue

Upvotes: 2

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