CODEWITHSUNDEEP
node.jsfirebasefirebase-realtime-databasesnapshot
Mr. Phil
Mr. Phil

Reputation: 1129

snapshot.ref is not a function

I'm trying to update a field from a snapshot, but even though the snapshot is not null and printed correctly, I can't seem to use ref.update() on it. I tried to follow this answer. What am I missing here?

My code: 

 ref.limitToLast(1).on('child_added', function(snapshot) {
    console.log(snapshot.val());
    var serial_number = String(snapshot.child("serial").val()); // 
    console.log(serial_number);
    snapshot.ref().update({ signed: 'true' });
// ...
}

Output:

output

Upvotes: 10

Views: 6573

Answers (1)

cartant
cartant

Reputation: 58400

The problem is that the answer you are referencing uses the previous version of Firebase and whilst the API is very close to the current version, there are a few differences.

There is a guide that discusses the changes and what needs to be done when upgrading from Firebase version 2 and version 3.

In particular, many no-argument getters have been changed to read-only properties:

BEFORE

// Reference
var key = ref.key();
var rootRef = ref.root();
var parentRef = ref.parent();

// Query
var queryRef = query.ref();

// DataSnapshot
ref.on("value", function(snapshot) {
  var dataRef = snapshot.ref();
  var dataKey = snapshot.key();
});

AFTER

// Reference
var key = ref.key;
var rootRef = ref.root;
var parentRef = ref.parent;

// Query
var queryRef = query.ref;

// DataSnapshot
ref.on("value", function(snapshot) {
  var dataRef = snapshot.ref;
  var dataKey = snapshot.key;
});

Upvotes: 16

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