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rubyif-statementmethodsreturn
Snowstormer
Snowstormer

Reputation: 248

How to access method return from if statement in Ruby?

I have a method that returns an array, like this:

def foobar(foo, bar)
  if foo != bar
    [foo, bar]
  end
end

Now, I want to call this method from inside my code using an if statement. How do I access the array values without having to duplicate the method?

if foobar("baz", "qux")
    foo = foobar("baz", "qux")
    puts foo[0], foo[1]
end

For further clarification, I mean something along the lines of $~ when you call a regex match in an if statement.

Upvotes: 0

Views: 55

Answers (1)

Jörg W Mittag
Jörg W Mittag

Reputation: 369458

Ruby has a concept called "local variables". You can assign objects to variables and then reference those variables:

if foo = foobar('baz', 'qux')
  puts foo[0], foo[1]
end

Note that Kernel#puts special-cases Array arguments and prints their elements on new lines, so your code is equivalent to the more idiomatic 

if foo = foobar('baz', 'qux')
  puts foo
end

Upvotes: 1

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