CODEWITHSUNDEEP
binaryintegererlang
Stratus3D
Stratus3D

Reputation: 4906

Convert Erlang integer to positional notation binary

I can convert an integer to a binary easily in Erlang:

integer_to_binary(11, 10).

The bits in the returned binary are in this case contains these bits:

0011000100110001

I'd like write a function to generate a binary containing the binary-notation of the number passed in. That is, the number eleven would look like this in bits:

1011

Is there an easy way to do this in Erlang?

Upvotes: 1

Views: 327

Answers (1)

Dogbert
Dogbert

Reputation: 222040

To convert an arbitrary sized unsigned integer to a binary consisting of the bytes in the integer, you can use binary:encode_unsigned/1 or binary:encode_unsigned/2.

1> binary:encode_unsigned(11).
<<"\v">>
2> binary:encode_unsigned(11) == <<0:4, 1:1, 0:1, 1:1, 1:1>>.
true

binary:encode_unsigned/1 will store the bytes in big endian representation. To store the bytes in little endian, you can use binary:encode_unsigned/2:

1> binary:encode_unsigned(123456789, little).
<<21,205,91,7>>
2> binary:encode_unsigned(123456789, big).
<<7,91,205,21>>

Upvotes: 2

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