Reputation: 277
I have an issue with an SQL Query. Lets take this example data
itemID catID attrib1 attrib2
1 1 10 5
2 1 10 7
3 1 5 10
4 2 18 15
I want to return the best item for each category (with attrib1 having priority over attrib2)
Obviously, SELECT catID, MAX(attrib1), MAX(attrib2) FROM test_table GROUP BY catID
doesn't work since it will return 10 & 10 for the 1st cat.
So is there anyway to tell MySQL to select max value from attrib2 row but only consider the ones where attrib1 is also max value ? i.e return the following data
catID attrib1 attrib2
1 10 7
2 18 15
Upvotes: 18
Views: 41695
Reputation: 700592
You can get the best attrib1 values, and then join in the attrib2 values and get the best of those for each attrib1 value:
select t2.catID, t2.attrib1, max(t2.attrib2)
from
(
select catID, max(attrib1) as attrib1
from test_table
group by catID
) t1
inner join test_table t2 on t2.catID = t1.catID and t2.attrib1 = t1.attrib1
group by t2.catID, t2.attrib1
Upvotes: 12
Reputation: 332681
Use:
SELECT x.catid,
x.max_attrib1 AS attrib1,
(SELECT MAX(attrib2)
FROM YOUR_TABLE y
WHERE y.catid = x.catid
AND y.attrib1 = x.max_attrib1) AS attrib2
FROM (SELECT t.catid,
MAX(t.attrib1) AS max_attrib1
FROM YOUR_TABLE t
GROUP BY t.catid) x
Upvotes: 2
Reputation: 12102
SELECT catID, max1, max2 FROM
((SELECT Max(attrib1) as max1, catID GROUP BY attrib1) as t1
INNER JOIN
(SELECT MAX(attrib2) as max2, catID GROUP BY attrib2) as t2
ON t1.catID = t2.catID) as t3
Upvotes: -2
Reputation: 14457
SELECT tt.catId, tt.attrib1, MAX(tt.attrib2)
FROM test_table tt
GROUP BY tt.catID, tt.attrib1
WHERE tt.attrib1 = (SELECT MAX(t2.attrib1) FROM test_table t2 WHERE t2.catID = tt.catID)
Upvotes: 1