Reputation: 3282
I am trying to make an expression tree that is capable of inserting two digit numbers. Right now, it can only insert digits 0 - 9 because of char's capabilities. My current code works on for postfix expressions, so when I make an expression tree for "+52" it evaluates to 10. If I want to make an expression for 10 * 2, it would not work because my code sees it as 3 digits and an operator.
Here's my code:
/*
* C++ Program to Implement Expression Tree
*/
#include <iostream>
#include <cstdlib>
#include <cstdio>
#include <cstring>
using namespace std;
/** class TreeNode **/
class TreeNode
{
public:
char data;
TreeNode *left, *right;
/** constructor **/
TreeNode(char data)
{
this->data = data;
this->left = NULL;
this->right = NULL;
}
};
/** class StackNode **/
class StackNode
{
public:
TreeNode *treeNode;
StackNode *next;
/** constructor **/
StackNode(TreeNode *treeNode)
{
this->treeNode = treeNode;
next = NULL;
}
};
class ExpressionTree
{
private:
StackNode *top;
public:
/** constructor **/
ExpressionTree()
{
top = NULL;
}
/** function to clear tree **/
void clear()
{
top = NULL;
}
/** function to push a node **/
void push(TreeNode *ptr)
{
if (top == NULL)
top = new StackNode(ptr);
else
{
StackNode *nptr = new StackNode(ptr);
nptr->next = top;
top = nptr;
}
}
/** function to pop a node **/
TreeNode *pop()
{
if (top == NULL)
{
cout<<"Underflow"<<endl;
}
else
{
TreeNode *ptr = top->treeNode;
top = top->next;
return ptr;
}
}
/** function to get top node **/
TreeNode *peek()
{
return top->treeNode;
}
/** function to insert character **/
void insert(char val)
{
if (isDigit(val))
{
TreeNode *nptr = new TreeNode(val);
push(nptr);
}
else if (isOperator(val))
{
TreeNode *nptr = new TreeNode(val);
nptr->left = pop();
nptr->right = pop();
push(nptr);
}
else
{
cout<<"Invalid Expression"<<endl;
return;
}
}
/** function to check if digit **/
bool isDigit(char ch)
{
return ch >= '0' && ch <= '9';
}
/** function to check if operator **/
bool isOperator(char ch)
{
return ch == '+' || ch == '-' || ch == '*' || ch == '/';
}
/** function to convert character to digit **/
int toDigit(char ch)
{
return ch - '0';
}
/** function to build tree from input */
void buildTree(string eqn)
{
for (int i = eqn.length() - 1; i >= 0; i--)
insert(eqn[i]);
}
/** function to evaluate tree */
double evaluate()
{
return evaluate(peek());
}
/** function to evaluate tree */
double evaluate(TreeNode *ptr)
{
if (ptr->left == NULL && ptr->right == NULL)
return toDigit(ptr->data);
else
{
double result = 0.0;
double left = evaluate(ptr->left);
double right = evaluate(ptr->right);
char op = ptr->data;
switch (op)
{
case '+':
result = left + right;
break;
case '-':
result = left - right;
break;
case '*':
result = left * right;
break;
case '/':
result = left / right;
break;
default:
result = left + right;
break;
}
return result;
}
}
};
/** Main Contains menu **/
int main()
{
string s;
cout<<"Expression Tree Test"<<endl;
ExpressionTree et;
et.buildTree("*52");
cout<<"\n\nEvaluated Result : "<<et.evaluate();
}
How do I make it so that the code is capable of handling and evaluating two digit numbers?
Upvotes: 0
Views: 655
Reputation: 416
First of all, '+ 5 2' is called prefix, not postfix notation. I am not sure if you want to convert your code to handle infix expressions(5+2), which would require you to rewrite the entire thing pretty much, or prefix expressions with multiple digits (+ 10 5), in either case you probably want to account for whitespace in the input string.
You should change Treenode.data to be an int instead of char, as realistically you expect "+ 10 5" to be parsed as three treeNodes in total, one of them holding "10".
The usual way of doing this is to first split your input string into tokens before passing a collection of tokens to buildTree. The input string "+ 10 5" has to first become a vector/array containing strings "+", "10", "5". Then later when you pass this collection to buildTree, each element will become a new TreeNode.
Other than that, looking at your code StackNode class seems redundant; you should be able to do everything you want with only having TreeNode.
Upvotes: 1