Reputation: 39907
Here is the code,
User.createCriteria().list(offset: filter.offset, max: filter.max) {
if (filter.first-name) eq('firstName', filter.first-name)
if (filter.last-name) eq('lastName', filter.last-name)
if (filter.email) eq('email', filter.email)
if (filter.status) eq('status', filter.status)
if (...) ...
.
.
order(filter.sort, 'desc')
order('name')
}
Is there any way to avoid if
s here?
Upvotes: 0
Views: 86
Reputation: 8587
And to make it even less readable but less repetitive you could include a map of your searchable items and try something like this :
filter.searchList=[first-name:'firstName',last-name:'lastName',
email:'email', status:'status']
User.createCriteria().list(offset: filter.offset, max: filter.max) {
filter.searchList?.each { k,v ->
!(filter."${k}" ?: eq(v, filter."${k}")
}
.
.
order(filter.sort, 'desc')
order('name')
}
Upvotes: 1
Reputation: 14559
What about a map?
User.createCriteria().list(offset: filter.offset, max: filter.max) {
[
'firstName' : filter.first-name,
'lastName' : filter.last-name,
'email' : filter.email,
'status' : filter.status
].findAll { it.value }.each { eq it.key, it.value }
order(filter.sort, 'desc')
order('name')
}
It could be even more dynamic, simply listing the property names.
Update: what about using closures as keys?
User.createCriteria().list(offset: filter.offset, max: filter.max) {
[
{ eq 'firstName', it } : filter.first-name,
{ eq 'lastName', it } : filter.last-name,
{ eq 'email', it } : filter.email,
{ eq 'status', it } : filter.status,
{ lt 'dob', it } : filter.dob
].findAll { it.value }.each { it.key(it.value) }
order(filter.sort, 'desc')
order('name')
}
I believe the it
param can be abstracted using something like curry
Upvotes: 1