CODEWITHSUNDEEP
javaspringserver-sent-eventseventemitter
aditya mujumdar
aditya mujumdar

Reputation: 71

SSE Emitter : Manage timeouts and complete()

I am writing a web app where multiple listeners(Evcentsource SSE clients JS) will be connected to my server . what i want to do is

  1. Store SSE emitter per connected listener : can be done in memory or any other means by assigning id to each client I am able to achieve this so far
  2. Now the question ; How do i send a response/event to specific client connected to my web app ? while doing this SSEEmmiters stored are either getting completed or timed out. how do i prevent this ? how do i keep sseEmmiter available open for infinite time (till client closes) and send events selectively .

Upvotes: 6

Views: 31215

Answers (4)

Abhinav Gupta
Abhinav Gupta

Reputation: 61

To solve the timeout issue, we used Long.MAX_VALUE as the timeout and it worked perfectly fine.

Upvotes: 2

Falah H. Abbas
Falah H. Abbas

Reputation: 512

If you want the sseEmmiter available open for infinite time, you can simply set the time out to -1L

and to send events selectively put all of sseEmmiters in a map with specific key to use it when you want to send event like i did in this code .

@Controller
@RequestMapping(path = "api/person")
public class PersonController {

 @Autowired
 private PersonRepository personRepository;
 private Map<String, SseEmitter> onPersonAddedSseEmitters = new ConcurrentHashMap<>();

 @PostMapping(path = "/add")
 public @ResponseBody
 String addPerson(@RequestBody Person person) {
   person.setId(new Random().nextLong());
   personRepository.save(person);
   onPersonAddedSseEmitters.forEach((key, sseEmitter) -> {
     try {
       if (person.getName().startsWith(key.split("-")[0])) {
         sseEmitter.send(person);
       }
     } catch (Exception ignored) {
       sseEmitter.complete();
       onPersonAddedSseEmitters.remove(key);
     }
   });
   return "Saved";
 }

 @GetMapping(path = "/onPersonAdded/{prefix}")
 public SseEmitter onPersonAdded(@PathVariable String prefix) {
   SseEmitter sseEmitter = new SseEmitter(-1L);
   onPersonAddedSseEmitters.put(prefix + "-" + new Random().nextLong(), sseEmitter);
   return sseEmitter;
 }
}

Upvotes: 10

Ronan Quillevere
Ronan Quillevere

Reputation: 3889

Details about how you should set a proper timeout. 2 ways of doing this with Spring

  1. Using the SseEmitter constructor 
SseEmitter emitter = new SseEmitter(15000L); // Example for 15s
  1. Using Spring property
spring.mvc.async.request-timeout: 15000

Quote from documentation

By default not set in which case the default configured in the MVC Java Config or the MVC namespace is used, or if that's not set, then the timeout depends on the default of the underlying server.

Upvotes: 4

rwfbc
rwfbc

Reputation: 998

You need to set the timeout on the SseEmitter. The default timeout is rather short.

The SseEmitter timeout is in milliseconds. It is a session timeout, not affected by activity on the session.

The timeout needs to be set to the expected duration of the session, in milliseconds. So, 86400000 (or more) is entirely appropriate.

Upvotes: 6

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