Reputation: 811
I have a bar chart with x and y values in D3 and I want to color my bars depending on the value of y. If y is smaller then 6 then it should be one color and if otherwise I want another color for it.
This is my code so far. This is working just for one value.
var data = [
{x: 2, y: 4},
{x: 5, y: 8},
{x: 8, y: 10}
];
bars.selectAll(".rect")
.data(data)
.enter().append("rect")
.attr("class", "rect")
.attr("x", function(d) { return x(d.x); })
.attr("y", function(d) { return y(d.y); })
.attr("height", function(d) { return h - y(d.y); })
.attr("width", 15)
.attr("fill", function(d){
return colorPicker(d);
});
function colorPicker(v){
if(v<=6) { return "#666666"}
else if (v > 6){ return "#FF0033";}
}
Do you have any idea how should I change this ? Thanks in advance!
Upvotes: 3
Views: 5870
Reputation: 102174
The simplest way for setting the colour according to that rule is using a ternary operator:
.attr("fill", function(d){ return d.y > 6 ? "#FF0033" : "#666666"});
Check the demo:
var w = 300, h = 100, padding = 20;
var svg = d3.select("body")
.append("svg")
.attr("width", w)
.attr("height", h);
var data = [{name: "foo", y:10},
{name: "bar", y:30},
{name: "baz", y: 5}];
var xScale = d3.scaleBand()
.range([0,w])
.domain(data.map(function(d){ return d.name}))
.paddingInner(0.2)
.paddingOuter(0.2);
var yScale = d3.scaleLinear()
.range([h - padding, 0])
.domain([0, d3.max(data, function(d){ return d.y})]);
var xAxis = d3.axisBottom(xScale);
var bars = svg.selectAll(".bars")
.data(data)
.enter()
.append("rect");
bars.attr("x", function(d){ return xScale(d.name)})
.attr("width", xScale.bandwidth())
.attr("y", function(d){ return yScale(d.y)})
.attr("height", function(d){ return h - padding - yScale(d.y)})
.attr("fill", function(d){ return d.y > 6 ? "#FF0033" : "#666666"});
var gX = svg.append("g")
.attr("transform", "translate(0," + (h - padding) + ")")
.call(xAxis);
<script src="https://d3js.org/d3.v4.min.js"></script>
However, if you want to keep that function, you have to call colorPicker
using d.y
as an argument, not d
:
colorPicker(d.y)
Check the demo:
var w = 300, h = 100, padding = 20;
var svg = d3.select("body")
.append("svg")
.attr("width", w)
.attr("height", h);
var data = [{name: "foo", y:10},
{name: "bar", y:30},
{name: "baz", y: 5}];
var xScale = d3.scaleBand()
.range([0,w])
.domain(data.map(function(d){ return d.name}))
.paddingInner(0.2)
.paddingOuter(0.2);
var yScale = d3.scaleLinear()
.range([h - padding, 0])
.domain([0, d3.max(data, function(d){ return d.y})]);
var xAxis = d3.axisBottom(xScale);
var bars = svg.selectAll(".bars")
.data(data)
.enter()
.append("rect");
bars.attr("x", function(d){ return xScale(d.name)})
.attr("width", xScale.bandwidth())
.attr("y", function(d){ return yScale(d.y)})
.attr("height", function(d){ return h - padding - yScale(d.y)})
.attr("fill", function(d){return colorPicker(d.y);});
function colorPicker(v){
if(v<6) { return "#666666"}
else{ return "#FF0033";}}
var gX = svg.append("g")
.attr("transform", "translate(0," + (h - padding) + ")")
.call(xAxis);
<script src="https://d3js.org/d3.v4.min.js"></script>
Upvotes: 5