CODEWITHSUNDEEP
javaarraysarraylistforeach
Vlad Demyan
Vlad Demyan

Reputation: 363

Iterating in for-each loop Java

I have an ArrayList,where I search for needed element and then add the needed part of it to another ArrayList. The problem is that if I want to keep searching for the words,not only one word,I don't know how to keep going on the elements through the loop. With the using of iterator, I wouldn't be able to search for things I need.

public static  ArrayList<String> FindWord(){
ArrayList<String> rewrite=new ArrayList<>();//
    ArrayList<String> word=Reading();// rewrites the data from one string to other
    String userinput=Chat();
  for(String elmt:word){
        if (elmt.contains(userinput) && elmt.contains("=")) {
                String[] parts=elmt.split("\\=");
                rewrite.add(parts[1]);
             // here I must do something like word.next
  }

    }
   System.out.println(rewrite);
    return rewrite;  // RETURNS THE SYNONIM OF THE WORD
}

So,it goes like if I input "hello", it will find me the word "greeting",which is a synonim in my text file. If I input "awesome", it will find the word "thanks", but if I input both of them it will input an empty array, like nothing is found instead of " greeting, thanks"

UPD: The Reading() returns:

public static ArrayList<String> Reading() {
    Scanner inputreader = null;
    try {
        inputreader = new Scanner(new FileInputStream("D:\\sinonims.txt"));
    }catch (FileNotFoundException e1) {                // OPENS FILE WITH SINONIMS
        e1.printStackTrace();
        System.out.println("File not found");
        System.exit(0);
    }
    ArrayList<String> Sins=new ArrayList();
   while(inputreader.hasNextLine()){
      String l=inputreader.nextLine();
       Sins.add(l);   // REWRITES DATA FROM FILE TO ARRATLIST
   }
    inputreader.close();
    System.out.print(Sins);
    return Sins;
}

public static String Chat(){ System.out.println("Let's start talking."); Scanner in=new Scanner(System.in); String line=in.nextLine(); return line; }

Upvotes: 0

Views: 181

Answers (4)

Sanket Makani
Sanket Makani

Reputation: 2489

You should split the input string userinput with some specific delimiter.

Then for each word, Iterate through the splitted array and give each word as input , Find its Synonym with your technique and add it to the arraylist.

This can be implemented by doing some changes in your code.

public static  ArrayList<String> FindWord()
{
    ArrayList<String> rewrite=new ArrayList<>();
    ArrayList<String> word=Reading();
    String userinput=Chat();
    String inputs[]=userinput.split(","); //Considering delimiter is comma(",") in user input

    for(String input : inputs) //Giving each word as input at a time and search for it in word String
    {
        for(String elmt:word)
        {
            if (elmt.contains(input) && elmt.contains("=")) 
            {
                    String[] parts=elmt.split("\\=");
                    rewrite.add(parts[1]);
            }
        }
    }
    System.out.println(rewrite);
    return rewrite;  // RETURNS THE SYNONIM OF THE WORD
}

So Here I am considering that the input is with delimiter Comma(",") so I have splitted input string with Comma(",") as you have given description in comments about your problem with space as delimiter.

When you will print the ArrayList, Automatically Output will be printed in separated manner with comma(, ).

So for Input : hello,awesome It will give output as greeting, thanks.

Upvotes: 1

VNT
VNT

Reputation: 974

you can create another arraylist and add your userinput values one by one into that list . you can iterate this newly created arraylist by using new for each loop on top of the current for each loop.

Upvotes: 1

OneCricketeer
OneCricketeer

Reputation: 191743

If you are trying to accept many inputs, you'll need to loop around the input & for loop.

The for loop already loops over all the words.

Note: I replaced contains for startsWith to prevent you catching the word on the other side of the equals 

static ArrayList<String> word=Reading();

public static  ArrayList<String> FindWord(){
    ArrayList<String> rewrite=new ArrayList<>();
    String userinput = "" ;
    while (true) {
        userinput=Chat();
        if (userinput.equals("quit")) break;
        for(String elmt:word){
            if (elmt.startsWith(userinput) && elmt.contains("=")) {
                String[] parts=elmt.split("\\=");
                rewrite.add(parts[1]);
            }
    }
   System.out.println(rewrite);
   return rewrite;  // RETURNS THE SYNONIM OF THE WORD
}

I can't really say this is the best way to approach your problem because it seems you need a Hashmap, not an Arraylist

Upvotes: 1

Subhasish Bhattacharjee
Subhasish Bhattacharjee

Reputation: 153

contains fetches you exact match, split the text and match accordingly, store the results in new array list

Upvotes: 1

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