CODEWITHSUNDEEP
pythonprinting
mashareq
mashareq

Reputation: 21

(Python 3) avoid printing comma at the end in print(variableName,end=',')

I have a code that print x number of numbers. Firstly, I asked for the serious length. Then print all the previous numbers (from 0 to x).

My question is that: when printing these number, I want to separate between them using comma. I used print(a,end=',') but this print a comma at the end also. E.g. print like this 1,2,3,4,5, while the last comma should not be there.

I used if statement to overcome this issue but do not know if there is an easier way to do it.

n=int(input("enter the length "))
a=0
if n>0:      
    for x in range(n):
        if x==n-1:
            print(a,end='')
        else:
            print(a,end=',')
        a=a+1

Upvotes: 2

Views: 1529

Answers (2)

Sumner Evans
Sumner Evans

Reputation: 9157

The most Pythonic way of doing this is to use list comprehension and join:

n = int(input("enter the length "))
if (n > 0):
    print(','.join([str(x) for x in range(n)]))

Output:

0,1,2

Explanation:

  • ','.join(...) joins whatever iterable is passed in using the string (in this case ','). If you want to have spaces between your numbers, you can use ', '.join(...).

  • [str(x) for x in range(n)] is a list comprehension. Basically, for every x in range(n), str(x) is added to the list. This essentially translates to:

    data = []
for (x in range(n))
    data.append(x)

Upvotes: 1

Artyer
Artyer

Reputation: 40801

A Pythonic way to do this is to collect the values in a list and then print them all at once.

n=int(input("enter the length "))
a=0
to_print = []  # The values to print
if n>0:      
    for x in range(n):
        to_print.append(a)
        a=a+1
print(*to_print, sep=',', end='')

The last line prints the items of to_print (expanded with *) seperated by ',' and not ending with a newline.

In this specific case, the code can be shortened to:

print(*range(int(input('enter the length '))), sep=',', end='')

Upvotes: 0

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