Reputation: 23
I'm having a seg fault when executing the following code:
program test
call sub ('dave')
end program test
subroutine sub (arr)
character (*) :: arr
character (20) :: upperc
arr = upperc (arr)
return
end subroutine sub
character (*) function upperc (str)
integer i, l
character (*) :: str
upperc = str
l = len (str)
do i = 1, l
icode = ichar (str (i:i))
if ((icode >= ichar ('a')).and.(icode <= ichar ('z'))) then
upperc (i:i) = char (ichar ('A') + icode - ichar('a'))
end if
enddo
return
end function upperc
The seg fault occurs on the following line:
arr = upperc (arr)
Here's the compilation and GDB runtime output:
[dave@VM-15 ~]$ gfortran -g -Wall test.f90
[dave@VM-15 ~]$ gdb
GNU gdb (GDB) Red Hat Enterprise Linux 7.6.1-80.el7
Copyright (C) 2013 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law. Type "show copying"
and "show warranty" for details.
This GDB was configured as "x86_64-redhat-linux-gnu".
For bug reporting instructions, please see:
<http://www.gnu.org/software/gdb/bugs/>.
(gdb) file ./a.out
Reading symbols from /home/dave/a.out...done.
(gdb) run
Starting program: /home/dave/./a.out
Program received signal SIGSEGV, Segmentation fault.
0x00007ffff70f1fa3 in __memmove_ssse3_back () from /lib64/libc.so.6
Missing separate debuginfos, use: debuginfo-install glibc- 2.17-106.el7_2.8.x86_64 libgcc-4.8.5-4.el7.x86_64 libgfortran-4.8.5-4.el7.x86_64 libquadmath-4.8.5-4.el7.x86_64
(gdb) backtrace
#0 0x00007ffff70f1fa3 in __memmove_ssse3_back () from /lib64/libc.so.6
#1 0x000000000040078c in sub (arr='dave', _arr=4) at test.f90:13
#2 0x00000000004008e9 in test () at test.f90:3
#3 0x000000000040091f in main (argc=1, argv=0x7fffffffe7b3) at test.f90:5
#4 0x00007ffff6fc3b15 in __libc_start_main () from /lib64/libc.so.6
#5 0x0000000000400669 in _start ()
(gdb) q
A debugging session is active.
Inferior 1 [process 20941] will be killed.
[dave@VM-15 ~]$
I get a funny feeling it has something to do with the fact that I'm passing a literal, but maybe not.
In an attempt to fix it, I tried the following instead, and it works fine:
program test2
character(20) text
text = 'dave'
call sub (text)
end program test2
subroutine sub (arr)
character (*) :: arr
character (20) :: upperc
arr = upperc (arr)
return
end subroutine sub
character (*) function upperc (str)
integer i, l
character (*) :: str
upperc = str
l = len (str)
do i = 1, l
icode = ichar (str (i:i))
if ((icode >= ichar ('a')).and.(icode <= ichar ('z'))) then
upperc (i:i) = char (ichar ('A') + icode - ichar('a'))
end if
enddo
return
end function upperc
Can anyone tell me what is going on?
Upvotes: 2
Views: 650
Reputation: 10606
The problem is that the subroutine sub
writes into the variable text
from program test2
. When you do not give a variable as an agrument to sub
, but just 'dave'
like in the first program test
, Fortran intends to overwrite an area in memory, which is not assigned as a variable. This leads to the segmentation fault.
Below you see your working example. Note two changes:
the length of the character text
was set to 6 instead of 20. This was done to demonstrate that thing still fit together, as the subroutine sub
takes an argument of arbitrary length.
We write 2 times the value of variable text
to the console and it was changed by call sub(text)
program test3
character(6) text
text = 'dave'
write(*,*) text
call sub (text)
write(*,*) text
end program test3
subroutine sub (arr)
character (*) :: arr
character (20) :: upperc
arr = upperc (arr)
return
end subroutine sub
character (*) function upperc (str)
integer i, l
character (*) :: str
upperc = str
l = len (str)
do i = 1, l
icode = ichar (str (i:i))
if ((icode >= ichar ('a')).and.(icode <= ichar ('z'))) then
upperc (i:i) = char (ichar ('A') + icode - ichar('a'))
end if
enddo
return
end function upperc
Upvotes: 2