CODEWITHSUNDEEP
pythonlistprintingtuples
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Reputation: 2429

How to break down and print two list of lists together in Python?

Here are two lists:

a_value = [[0.234, 0.88,0.98],[0.923,0.777,0.87],[0.77,0.98,0.89]]
b_value = [[(1,1),(1,2),(1,3)],[(1,1),(1,2),(1,3)],[(1,1),(1,2),(1,3)]]

I need to join the two lists such that I have output that prints as:

Set1
b_value (1,1) = a_value 0.234
b_value (1,2) = a_value 0.88
b_value (1,3) = a_value 0.98
Set2
b_value (1,1) = a_value 0.923
b_value (1,2) = a_value 0.777
b_value (1,3) = a_value 0.87
Set 3
b_value (1,1) = a_value 0.77
b_value (1,2) = a_value 0.98
b_value (1,3) = a_value 0.89

The code that I have attempted looks like:

print("\n".join([('b_value{} a_value={}'.format(i,j)) for i,j in zip(b_value,a_value)]))

Output:

b_value[(1, 1), (1, 2), (1, 3)] a_value=[0.234, 0.88, 0.98]
b_value[(1, 1), (1, 2), (1, 3)] a_value=[0.923, 0.777, 0.87]
b_value[(1, 1), (1, 2), (1, 3)] a_value=[0.77, 0.98, 0.89]

I am not sure how to modify the code such that it breaks down the list of lists and also separates them into "Sets".

Upvotes: 0

Views: 614

Answers (4)

Moses Koledoye
Moses Koledoye

Reputation: 78546

Since you only need to print the values and not build a list, you should use for loops instead of the list comprehension. And then you also need to zip the sublists in a nested loop to place their items side-by-side:

for idx, (i ,j) in enumerate(zip(b_value,a_value), 1):
    print("Set{}".format(idx))
    for a,b in zip(i,j):
        print('b_value {} = a_value {}'.format(a,b))

Set1
b_value (1, 1) = a_value 0.234
b_value (1, 2) = a_value 0.88
b_value (1, 3) = a_value 0.98
Set2
b_value (1, 1) = a_value 0.923
b_value (1, 2) = a_value 0.777
b_value (1, 3) = a_value 0.87
Set3
b_value (1, 1) = a_value 0.77
b_value (1, 2) = a_value 0.98
b_value (1, 3) = a_value 0.89

Upvotes: 4

pablobordons
pablobordons

Reputation: 51

I don't know how general you want this code, but this prints out want you want I think:

for myset in zip(a_value,b_value):
    for i in range(len(myset) + 1):
        print("b_value " + str(myset[1][i]) + " = a_value " + str(myset[0][i]))

Upvotes: 1

Darkstarone
Darkstarone

Reputation: 4730

You need to flatten the two lists, if you want to do this in a single line I'd use itertools.chain:

from itertools import chain

a_value = [[0.234, 0.88,0.98],[0.923,0.777,0.87],[0.77,0.98,0.89]]
b_value = [[(1,1),(1,2),(1,3)],[(1,1),(1,2),(1,3)],[(1,1),(1,2),(1,3)]]

print("\n".join([('b_value{} a_value={}'.format(i,j)) for i,j in zip(chain.from_iterable(b_value),chain.from_iterable(a_value))]))

However, if you need a faster method of flattening, use a few extra lines:

a_value = [[0.234, 0.88,0.98],[0.923,0.777,0.87],[0.77,0.98,0.89]]
b_value = [[(1,1),(1,2),(1,3)],[(1,1),(1,2),(1,3)],[(1,1),(1,2),(1,3)]]

flat_a = [item for sublist in a_value for item in sublist]
flat_b = [item for sublist in b_value for item in sublist]

print("\n".join([('b_value{} a_value={}'.format(i,j)) for i,j in zip(flat_b,flat_a)]))

Upvotes: 4

rofls
rofls

Reputation: 5115

It seems you have the formatting part ok, but having trouble combining the lists correctly. Why not flatten them first?

a = [[0.234, 0.88,0.98],[0.923,0.777,0.87],[0.77,0.98,0.89]]
b = [[(1,1),(1,2),(1,3)],[(1,1),(1,2),(1,3)],[(1,1),(1,2),(1,3)]]

flat_a = [item for sublist in a for item in sublist]
flat_b = [item for sublist in b for item in sublist]
zip(flat_a, flat_b)

Upvotes: 2

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