CODEWITHSUNDEEP
chexavruart
user6318361
user6318361

Reputation: 51

Sending Hex through UART

I am trying to send a hexadecimal data over UART to my AVR. The problem is, I can't send more than two pair of hex. I need to send more than two, like 9-10.

For example:

I could only send 0x2f and 0x3f. If I send more than that, its always minus.

I need to send 0xff234f3a3f.

My code:

sendString("wish me luck\n");

while(1)
{               
    char str[35];
    int i;

    printf("enter the code :\n");
    scanf("%x", &i);
    printf("%#x (%d)\n",i,i);
}

What did I do wrong?

Upvotes: 2

Views: 2656

Answers (2)

rabatra
rabatra

Reputation: 111

You can achieve this by storing the data you wish to send in a software buffer and as soon as avr sends the 1byte of uart data fill the uart register with the byte from Software buffer. You can do something like this:-

char ar[] = "hello";
for (i = 0; i < strlen(ar); i++) {
    while ((UCSR0A & (1<<UDRE0)) == 0);
    UDR0 = ar[i]; 
}

Hope this helps

Upvotes: 1

Dheeraj Kumar
Dheeraj Kumar

Reputation: 387

AVR UART has a size limitation as it is in embedded environment so the UART buffer is only 8/16 bits . You are able to send 2 bytes of data , to send more you need to make a loop to send the remaining data bytes.

Upvotes: 0

Related Questions