CODEWITHSUNDEEP
iosswiftstring
Mark Carols
Mark Carols

Reputation: 433

How to get rid of a "non-breaking space" inside a Swift string?

I retrieved some strings from AddressBook.framework's ABRecordCopyValue method by casting the returned value of takeRetainedValue() as a String object.

let unmanagedFirstNameProperty = ABRecordCopyValue(person, kABPersonFirstNameProperty)
if unmanagedFirstNameProperty != nil {
    contactFirstName = unmanagedFirstNameProperty!.takeRetainedValue() as? String
}

let formattedName:String = contactFirstName.replaceOccurrences(of: " ", with: "")
print(formattedName)

I want to get rid of the spaces inside this String object by calling replaceOccurrences(of:with:) method, but that doesn't work (the spaces are still there after I call this method) and I was told by the Apple Framework Reference that this is usually because of the string encoding, containing "non-break spaces" which I've heard a lot about, but I have no idea how to make a "non-break space" into a normal space. Is this even possible? If so, what would be the best approach to make the characters inside a String compatible with the replaceOccurrences(of:with:) method?

Upvotes: 0

Views: 3894

Answers (1)

Son of a Beach
Son of a Beach

Reputation: 1779

In your code, where you have contactFirstName.replaceOccurrences(of: " ", with: "") make sure that within the quotes, the space character should be typed in with the option key held down. If you type a space with the option key held down, you should get a non-breaking space.

Then you can replace it with a normal space, or an empty string if you wish.

Alternatively, as suggested in comments, the following may be more readable:

contactFirstName.replaceOccurrences(of: "\u{00A0}", with: "")

That way it doesn't look like a normal space in code.

Upvotes: 5

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