error C2064: term does not evaluate to a function taking 0 arguments

Question

In some code I'm writing, I have the following line, which gives me error C2064:

rs_opCodes[cur_block]();

rs_opCodes is defined as such:

typedef void (rsInterpreter::*rs_opCode)();
rs_opCode rs_opCodes[NUM_OPCODES];

Does anyone know why I'm recieved error C2064?

Answer 1

You defined rs_opCode as a pointer to a member function (of class rsInterpreter). To call such a beast, you need the sytax

(object.*rs_opCodes[cur_block])();

or

(pointer->*rs_opCodes[curr_block])();

Answer 2

You have to use the syntax of method pointer call, but you need an object to which make the actual call. Note that the typedef stablishes that you're defining pointers to a method of objects of type rsInterpreter, so you need an object of that type:

rsInterpreter r;
(r.*rs_opCodes[cur_block])();

However, the whole idea of this doesn't make much sense to me. You're writting an array of method pointers to be called in objects... I can't, at first thought, come up out of my mind of an usable example of this type of code...

Answer 3

You defined rs_opCode to be a method pointer but you are using it as function pointer.