CODEWITHSUNDEEP
javascriptnode.jsasynchronousasync-awaitbabeljs
IronWaffleMan
IronWaffleMan

Reputation: 2692

Babel-node script failed with 'Unexpected token' syntaxError on 'await' line

I have a script that's reading a bunch of info from Firebase, and then processes it. This involves some async calls to external data sources, for which I want to use async and await. I've done this successfully, in this very npm project, so I don't see why it's not working now. This is my .babelrc file:

{
  "presets": ["es2015", "stage-0", "react"],
  "plugins": ["syntax-async-functions","transform-regenerator"]
}

And this is the gist of my code:

var config = {
    apiKey: "key",
    authDomain: "myProject.firebaseapp.com",
    databaseURL: "https://myProject.firebaseio.com",
    storageBucket: "myProject.appspot.com",
    messagingSenderId: "id"
};
Firebase.initializeApp(config);

var dbRef = Firebase.database().ref();

getAllFirebaseDocs(dbRef);

async function getAllFirebaseDocs(dbRef) {
	return dbRef.once('value').then(function(snapshot) {
		var items = snapshot.val();
        for (key in items) {
            var priceUrl = "some.url.com"
		    items[key] = await requestPrices(items[key], priceUrl);
        }
    }
}

It's failing on the await line with SyntaxError: testScript.js: Unexpected token. And a bunch of code with weird box characters and 33m and 39m in it, like this: [33m][39m[1m,[22m priceUrl[94m[1m)[22m[39m[1m;[22m.

I'm running the script with babel-node testScript.js. I know this works, since I have another script that I run in the same project with babel-node and it has async parts that work fine... not sure what I've missed in this one. If it matters, babel-node -V gives v6.4.0.

Upvotes: 0

Views: 183

Answers (1)

robertklep
robertklep

Reputation: 203241

You can only use await within functions that are marked async. In your case, you're running it inside a function (the callback to .then()) that isn't marked as such.

You can use this:

return dbRef.once('value').then(async function(snapshot) { ... });

But since you're using async/await already, you might as well rewrite your code to this:

async function getAllFirebaseDocs(dbRef) {
  let snapshot = await dbRef.once('value');
  let items    = snapshot.val();
  for (let key in items) {
    let priceUrl = "some.url.com"
    items[key] = await requestPrices(items[key], priceUrl);
  }
  // I assume that you want to return `items`; your original code doesn't return anything.
  return items;
}

Upvotes: 2

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