Reputation: 593
I am having hard time trying to produce a grid with four coefficients' plot from four non-nested linear random effects models using the sj.plot
package.
I am not married to this package so feel free to suggest other routes (ggplot2
solutions better than coefplot2::coefplot2
).
Desired output: a grid with the four coefficients' plots next to each other.
Reproducing the models:
data("sleepstudy")
sleepstudy$var2 <- rnorm(n=nrow(sleepstudy), mean=0, sd=1)
sleepstudy$var3 <- rnorm(n=nrow(sleepstudy), mean=10, sd=5)
M1 <- lmer(Reaction ~ Days + (1|Subject), data=sleepstudy, REML = FALSE)
M2 <- lmer(Reaction ~ Days + var2 + (1|Subject), data=sleepstudy, REML = FALSE)
M3 <- lmer(Reaction ~ Days + var3 + (1|Subject), data=sleepstudy, REML = FALSE)
M4 <- lmer(Reaction ~ Days + var2 + var3 + (1|Subject), data=sleepstudy, REML = FALSE)
Reproducing the problems. Attempt #1 (sjp.lmm
)
> sjp.lmm(M1, M2, M3, M4)
Computing p-values via Kenward-Roger approximation. Use `p.kr = FALSE` if computation takes too long.
Computing p-values via Kenward-Roger approximation. Use `p.kr = FALSE` if computation takes too long.
Error in data.frame(betas, p = ps, pa = palpha, shape = pointshapes, grp = fitcnt, :
arguments imply differing number of rows: 3, 2, 1
Reproducing the problems. Attempt #2 (sjp.lmer
+ plot_grid
)
plot.1 <- sjp.lmer(fit=M1,type="fe.std",
p.kr=FALSE,
sort.est = "sort.all",
y.offset = 0.4,
fade.ns = TRUE,
facet.grid = T)
plot.2 <- sjp.lmer(fit=M2,type="fe.std",
p.kr=FALSE,
sort.est = "sort.all",
y.offset = 0.4,
fade.ns = TRUE,
facet.grid = T)
plot.3 <- sjp.lmer(fit=M3,type="fe.std",
p.kr=FALSE,
sort.est = "sort.all",
y.offset = 0.4,
fade.ns = TRUE,
facet.grid = T)
plot.4 <- sjp.lmer(fit=M4,type="fe.std",
p.kr=FALSE,
sort.est = "sort.all",
y.offset = 0.4,
fade.ns = TRUE,
facet.grid = T)
plot_grid(list(plot.1,plot.2,plot.3,plot.4))
> plot_grid(list(plot.1,plot.2,plot.3,plot.4))
Error in gList(list(wrapvp = list(x = 0.5, y = 0.5, width = 1, height = 1, :
only 'grobs' allowed in "gList"
Is there a way to obtain this plot?
Versions: [6] sjPlot_2.1.1
, ggplot2_2.1.0
, lme4_1.1-12
, sjmisc_2.0.1
, gridExtra_2.2.1
, dplyr_0.5.0
.
Upvotes: 2
Views: 1186
Reputation: 7822
The return values of the sjPlot-functions return both a data frame and the plot-object, so you have to access the plot-object in the arguments:
plot_grid(list(plot.1$plot, plot.2$plot, plot.3$plot, plot.4$plot))
Edit:
I saw you found a bug in the sjp.lmm()
function and could fix it. If you download the latest snapshot from GitHub (https://github.com/sjPlot/devel), this will work:
sjp.lmm(M1, M2, M3, M4)
Upvotes: 2
Reputation: 145755
I don't know anything about this sjPlot
class, but it looks like it bundles a bunch of stuff to the plot in a list. plot_grid
, grid.arrange
and the like don't know how to deal with the extra stuff, but they can handle the ggplot
part, which is called plot
:
plot_grid(lapply(list(plot.1,plot.2,plot.3,plot.4), "[[", "plot"))
I am a bit surprised because it seems like at least some of the bundled information is duplicative. For example, plot.1$data
has a small data frame which seems to be a copy (or subset?) of the data that is already bundled with the plot, plot.1$plot$data
. Maybe it's more different and there's good reason for it in more complex cases.
Upvotes: 0