Reputation: 35
I have a data set (discrete monthly return series) with two dozen columns representing data series, c.100 rows representing month-end time-series. The data in the set represents the monthly performance of each data set.
Each series has run for a different length of time and is updated to a different length of time.
My conundrum is; I am looking to find, for each series, the dates of both the earliest data point and the most recent data point. I was hoping to do this by way of referencing the row headers (date) in column A. To do this I would need to know the row number of the earliest data point.
I can get the value of the earliest data point using a CSE IndexMatch, but what I really need is the reference.
EDIT
Tom, this is the data set;
As you can see, each data set starts (and finishes) at a different date.
In a summary sheet I am putting the date range for which each respective data series has data, that is why I need the row value (so that I can lookup the dates).
Upvotes: 1
Views: 4611
Reputation: 34180
So your formula was fine, you just needed to MATCH in column G and INDEX into column A:-
=INDEX('Discrete Monthly Returns'!A3:A1048576,MATCH(FALSE,ISBLANK('Discrete Monthly Returns'!G3:G1048576),0))
I appreciate that you would want the start date to appear somewhere else, but this is just an illustration of how to use the formula
Upvotes: 1
Reputation: 9809
This example teaches you how to find the cell address of the maximum value in a column.
MAX
function to find the maximum value in column A.MATCH
function to find the row number of the maximum value.Explanation: the MATCH
function reduces to =MATCH(12,A:A,0)
, 7. The MATCH
function returns the position of the maximum value in column A. Set the third argument to 0
to return an exact match.
ADDRESS
function to return the cell address.Explanation: the ADDRESS
function reduces to =ADDRESS(7,1)
, $A$7
. The first argument specifies the row number. The second argument specifies the column number.
http://www.excel-easy.com/examples/locate-maximum-value.html
The answer is copy-paste work from the above link, but pasted here as reference.
Upvotes: 1