CODEWITHSUNDEEP
javascriptarraysobjectindexing
Espen Klem
Espen Klem

Reputation: 331

Javascript: Finding an object's index in an array, not knowing the index, only the object

I have an array of objects and I want to remove one of the objects.

[
  {"field":"ingredients","gte":"egg","lte":"egg"},
  {"field":"ingredients","gte":"bakepulver","lte":"bakepulver"},
  {"field":"ingredients","gte":"hvetemel","lte":"hvetemel"}
]

I don't know the index of the object I want to remove, but I know the whole object. I.e:

{"field":"ingredients","gte":"bakepulver","lte":"bakepulver"}

I need to find the object's index by it's full content (all properties), not just by field, gte or lte. How do I find object's index in the array with just plain JavaScript?

Upvotes: 2

Views: 171

Answers (5)

trincot
trincot

Reputation: 350272

As I understand from your further comments, you need a solution for this specific case only, where the objects consist of 3 given properties. Therefore I would suggest this ES6 solution:

var data = [
  { "field": "ingredients", "gte": "egg", "lte": "egg" },
  { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" },
  { "field": "ingredients", "gte": "hvetemel", "lte": "hvetemel" }];
var search = { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" };

var index = data.findIndex(
    a => a.field == search.field && a.gte == search.gte && a.lte == search.lte);

console.log(index);

If you don't have full ES6 support, then:

var data = [
  { "field": "ingredients", "gte": "egg", "lte": "egg" },
  { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" },
  { "field": "ingredients", "gte": "hvetemel", "lte": "hvetemel" }];
var search = { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" };

var index = -1;
data.some(function (a, i) {
    if (a.field == search.field && a.gte == search.gte && a.lte == search.lte)
        return index = i, true;
});
console.log(index);

Upvotes: 1

RizkiDPrast
RizkiDPrast

Reputation: 1725

I use old method of comparing object, by stringify it. try to review this one

var x = [{
  "field": "ingredients",
  "gte": "egg",
  "lte": "egg"
}, {
  "field": "ingredients",
  "gte": "bakepulver",
  "lte": "bakepulver"
}, {
  "field": "ingredients",
  "gte": "hvetemel",
  "lte": "hvetemel"
}];
var control = {
  "field": "ingredients",
  "gte": "bakepulver",
  "lte": "bakepulver"
};

function getIndex(arr, key) {
  var got = false,
    result = -1;
  arr.every(function(e, i) {
    if (JSON.stringify(e) === JSON.stringify(key)) {
      console.log('match found');
      result = i;
      return false;
    }
    return true;
  })
  return result;
}

console.log(getIndex(x, control));

Upvotes: 0

Nina Scholz
Nina Scholz

Reputation: 386578

You could iterate over the data and then check the length of the keys and every key, if it has the same content.

var data = [{ "field": "ingredients", "gte": "egg", "lte": "egg" }, { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" }, { "field": "ingredients", "gte": "hvetemel", "lte": "hvetemel" }],
    search = { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" },
    keys = Object.keys(search),
    index = -1;

data.some(function (a, i) {
    if (Object.keys(a).length === keys.length && keys.every(function (k) { return a[k] === search[k]; })) {
        index = i;
        return true;
    }
});

console.log(index);

ES6

var data = [{ "field": "ingredients", "gte": "egg", "lte": "egg" }, { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" }, { "field": "ingredients", "gte": "hvetemel", "lte": "hvetemel" }],
    search = { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" },
    keys = Object.keys(search),
    index = data.findIndex(a =>
        Object.keys(a).length === keys.length && keys.every(k => a[k] === search[k]));

console.log(index);

Upvotes: 2

Kaan
Kaan

Reputation: 86

You could use this code for your problem

var array = [
    {"field":"ingredients","gte":"egg","lte":"egg"},
    {"field":"ingredients","gte":"bakepulver","lte":"bakepulver"},
    {"field":"ingredients","gte":"hvetemel","lte":"hvetemel"}
];
var searchObject =      
    {"field":"ingredients","gte":"bakepulver","lte":"bakepulver"};

var indexOfSearchResult;

for (var i = 0; i < array.length; i++) {
    var checkEqualBool = true;
    for (var key in array[i]) {
        if(array[i][key]!=searchObject[key]){
            checkEqualBool = false;
            break;
        }
    }
    if(checkEqualBool){
        indexOfSearchResult = i;
        break;
    }
}

Upvotes: 0

guest271314
guest271314

Reputation: 1

You can use Object.keys(), Array.prototype.findIndex(), Array.prototype.every() to check if each property name, value, and object property names .length are equal.

let data = [
  {"field":"ingredients","gte":"egg","lte":"egg"},
  {"field":"ingredients","gte":"bakepulver","lte":"bakepulver"},
  {"field":"ingredients","gte":"hvetemel","lte":"hvetemel"}
];

let props = {"field":"ingredients","gte":"bakepulver","lte":"bakepulver"};
let keys = Object.keys(props);
let index = data.findIndex(o => keys.every(key => o[key] === props[key]) 
              && Object.keys(o).length === keys.length);

console.log(index);

Upvotes: 2

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