CODEWITHSUNDEEP
rubystring
AltBrian
AltBrian

Reputation: 2562

Get the first half of a string in ruby

I am trying to get the first half of a string. If the string length is an odd number, then round up. I am bit stuck on getting a half of a string.

def get_first_half_of_string(string)
  if string.size % 2 == 0
    string[1,4]
  else
    string[1,5]
  end
end

puts get_first_half_of_string("brilliant")

This returns rilli

Upvotes: 1

Views: 1750

Answers (4)

frostmatthew
frostmatthew

Reputation: 3298

When calling str[start, length] you need to use 0, not 1, as the start point. For the length you should just be able to divide the length by 2, so your method body only needs string[0, (string.length.to_f / 2).ceil]

https://ruby-doc.org/core-2.2.0/String.html#method-i-5B-5D

Upvotes: 2

Daniel Hilpoltsteiner
Daniel Hilpoltsteiner

Reputation: 11

Maybe you could divide the string size in half and round up if it is odd:

half = (string.size/2.to_f).ceil
string[0,half]

Upvotes: 1

Madh
Madh

Reputation: 131

Following previous answers, you could open String class:

class String
  def first_half
    self[0,(self.size/2.to_f).ceil]
  end
end

So you can do:

"ruby".first_half
=> "ru"
"hello".first_half
=> "hel"

Upvotes: 0

spickermann
spickermann

Reputation: 106812

I would do something like this:

def first_half_of_string(string)
 index = (string.size.to_f / 2).ceil
 string[0, index]
end

first_half_of_string("brilliant")
#=> "brill"

Upvotes: 1

Related Questions