CODEWITHSUNDEEP
pythondictionaryiterable-unpacking
Roberto
Roberto

Reputation: 2194

How to unpack a dictionary of list (of dictionaries!) and return as grouped tuples?

I have a data structure consisting of mixed dictionaries and lists. I am trying to unpack this so as to get tuples of the keys and all sub-values for each key.

I am working with list comprehensions, but just not getting it to work. Where am I going wrong?

I saw many other answers about unpacking a list-of-lists (e.g. 1,2), but could not find an example where a single key unpacks against multiple sub-values.

code:

dict_of_lists = {'A':[{'x':1},{'x':2}], 'B':[{'x':3},{'x':4}] }
print [(key,subdict[subkey],) for key in dict_of_lists.keys() for subdict in dict_of_lists[key] for subkey in subdict.keys()]

Upvotes: 8

Views: 17412

Answers (2)

Chris
Chris

Reputation: 22953

When list comprehensions become

  • long
  • unclear/hard to read
  • and most importantly, do not work

ditch them and go with the manual for loop(s) every time:

Python 2.x

def unpack(d):
    for k, v in d.iteritems():
        tmp = []
        for subdict in v:
            for _, val in subdict.iteritems():
                tmp.append(val)
        yield (k, tmp[0], tmp[1])


print list(unpack({'A':[{'x':1},{'x':2}], 'B':[{'x':3},{'x':4}] }))

Python 3.x

def unpack(d):
        for k, v in d.items():
            tmp = []
            for subdict in v:
                for _, val in subdict.items():
                    tmp.append(val)
            yield (k, *tmp) # stared expression used to unpack iterables were
                            # not created yet in Python 2.x                

print(list(unpack({'A':[{'x':1},{'x':2}], 'B':[{'x':3},{'x':4}] })))

Output:

[('A', 1, 2), ('B', 3, 4)]

Upvotes: 7

helloV
helloV

Reputation: 52383

Loop through the list of dicts and get only the values. Then combine with the dict key.

>>> for k,L in dict_of_lists.iteritems():
...   print tuple( [k]+[v for d in L for v in d.values()])

('A', 1, 2)
('B', 3, 4)

If you need a one liner:

>>> map(tuple, ([k]+[v for d in L for v in d.values()] for k,L in dict_of_lists.iteritems()))

[('A', 1, 2), ('B', 3, 4)]

Upvotes: 2

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