Reputation: 1879
I have a list of lists in the following format:
[['a'],['1'],['2'],['3'], ['b'],['4'],['5'],['6']]
My desired output is:
[['a', '1'], ['a', '2'], ['a','3'],['b', '4'],['b', '5'],['b', '6']]
or even better would be:
{'a':['1','2','3'], 'b':['4','5','6']}
Essentially, the "number values" are never the same size (think that a could include 1 2 and 3, and b could include 4 5 6 7 and 8, etc)
What would be the easiest way of doing this? Using regex?
Thanks
Upvotes: 0
Views: 55
Reputation: 3485
You can use a for
loop and check if the element is a digit or not:
d = {}
for i in lst:
if not i[0].isdigit(): # Check if element is a digit. If not, add a key with the current value of i[0]
d[i[0]] = []
current = i[0]
else:
d[current].append(i[0])
Output:
>>> d
{'a': ['1', '2', '3'], 'b': ['4', '5', '6']}
This is assuming everything in the list is a string
Upvotes: 2