CODEWITHSUNDEEP
arraysstringbashwhitespace
pUTa432
pUTa432

Reputation: 57

Insert spaces in the string array

I have the following array:

declare -a case=("060610" "080813" "101016" "121219" "141422")

I want to generate another array where the elements have whitespaces inserted appropriately as:

"06 06 10" "08 08 13" "10 10 16" "12 12 19" "14 14 22"

I got till handling the elements individually using sed as:

echo '060610' | sed 's/../& /g'

But I am not being able to do it while using the array. The sed confuses the white spaces in between the elements and I am left with the output:

echo "${case[@]}" | sed 's/../& /g'

Gives me:

06 06 10  0 80 81 3  10 10 16  1 21 21 9  14 14 22

Can someone help?

Upvotes: 1

Views: 244

Answers (2)

that other guy
that other guy

Reputation: 123470

You can use printf '%s\n' "${case[@]}" | sed 's/../& /g' to get each number on a separate line and avoiding the space problem:

$ declare -a case=("060610" "080813" "101016" "121219" "141422")

$ printf '%s\n' "${case[@]}" | sed 's/../& /g'
06 06 10
08 08 13
10 10 16
12 12 19
14 14 22

If you want it back into an array, you can use mapfile

Upvotes: 2

Barmar
Barmar

Reputation: 780974

You need to loop over the array, not echo it as a whole, because you don't get the grouping when you echo it.

declare -a newcase
for c in "${case[@]}"
do
    newcase+=("$(echo "$c" | sed 's/../& /g')")
done

Upvotes: 2

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