Reputation: 81
Using PyQt, I want to create an user interface which answers to this set of rules :
The main issue I have is that I do not find any Qt command to access the push button at a predefined position in the grid. What I found which is the closest from this is the function mouseClickEvent. Sadly, QtGui.QGridLayout.itemAtPosition(self.grid,*location).setEnabled(False) does not work, because QtGui.QGridLayout.itemAtPosition(self.grid,*location) is not a PushButton, but a QtWidget.
There is some pseudo-code below : it is written after a #.
import sys
import numpy as np
from PyQt4 import QtGui
class InterfaceGraphique(QtGui.QWidget):
def __init__(self,size):
super(InterfaceGraphique, self).__init__()
self.size=size
self.position=((size-1)//2,(size-1)//2)
self.initUI(size)
def initUI(self,size):
self.grid = QtGui.QGridLayout()
self.setLayout(self.grid)
names=list(map(lambda x: str(x),np.random.choice(10,size**2)))
positions = [(i, j) for i in range(size) for j in range(size)]
for position, name in zip(positions, names):
button = QtGui.QPushButton(name)
button.clicked.connect(self.mouseClickEvent)
self.grid.addWidget(button, *position)
self.move(300, 150)
self.setWindowTitle('Game')
self.show()
def mouseClickEvent(self):
button=self.sender()
idx = self.grid.indexOf(button)
location = self.grid.getItemPosition(idx)
# QtGui.QGridLayout.itemAtPosition(self.grid,*location).setEnabled(False)
# for neighbor in neighbors(location)
# QtGui.QGridLayout.itemAtPosition(self.grid,*neighbor).setEnabled(True)
self.position=location
size=5
def main():
app = QtGui.QApplication(sys.argv)
ex = InterfaceGraphique(size)
app.exec_()
if __name__ == '__main__':
main()
Upvotes: 1
Views: 671
Reputation: 11849
Assuming that neighbours
does what you want (you haven't included that bit of code), you want to call setEnabled()
on the widget of the QWidgetItem
.
self.grid.itemAtPosition(*neighbour).widget().setEnabled(True)
Upvotes: 2