CODEWITHSUNDEEP
pythonpygtk
Ingo
Ingo

Reputation: 1802

How to call a function in a pyGTK timeout?

When I try to call a function using a timeout in pyGtk, I receive the error message TypeError: second argument not callable. All I want to do is call a very simple function from within the time out. To illustrate my proble, I have simply prepared the function do_nothing to illustrate my problem.

def do_nothing(self):
    return True

# Do interval checks of the timer
def timed_check(self, widget):
    self.check_timing = gobject.timeout_add(500, self.do_nothing())

which does not work...

What am I doing wrong?

Upvotes: 1

Views: 639

Answers (3)

aggressivenoob
aggressivenoob

Reputation: 11

try instead:

self.check_timing = gobject.timeout_add(500, self.do_nothing, self)

Upvotes: 1

pyfunc
pyfunc

Reputation: 66729

Pass self.do_nothing and not self.do_nothing()

self.do_nothing is callable

self.do_nothing() returns a value and that return value is not a callable

Upvotes: 1

Adam Vandenberg
Adam Vandenberg

Reputation: 20671

You're calling the function:

self.do_nothing()

You want to pass the function:

self.do_nothing

Omit the parentheses.

Upvotes: 6

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