Reputation: 3417
I just downloaded the plugin XamJam.Screen and I have to implement it, the problem is that it is an interface. That said, I've never implemented interfaces in c # programming, and I wonder if anyone can advise me how to implement it, I tried but without success, the following code:
namespace Fimap.WebPart
{
public partial class HomePage : ContentView
{
public HomePage()
{
InitializeComponent();
Screen xyz = new getScreen();
var w = xyz.Size.Width;
}
public class getScreen : Screen
{
public ScreenSize Size
{
get
{
return Size;
}
}
}
}
}
the problem is that size 0 me back around. My goal is to take the width and height of the device.
Upvotes: 1
Views: 354
Reputation: 2296
You do not need to implement the interface yourself. If you installed the package through NUGET, you only need to call
var size = Plugin.XamJam.Screen.CrossScreen.Current.Size;
you can access the width and height of the screen with size.Width and size.Height
Please visit the project github home page and checkout the additional disclaimers on how the library works, provided by the author.
As you can see, the library is of limited use. There is probably a better way to achieve what ever it is that you are trying to do. Consider researching your actual use case / problem further.
Upvotes: 1