Reputation: 131
I want to plot the following function
I(x) = 5*(1+x/2) for -2 < x < 0
5*(1-x/2) for 0 < x < 2
0 elsewhere
I use the following script:
clc; close all; clear all;
L = 4;
x = -20:1:20;
I((-L/2) < x & x<0) = 5*(1 + x/(L/2));
I(0 < x & x < (L/2)) = 5*(1 - x/(L/2));
plot (x,I), grid
It does not work. Could you please help me?
Upvotes: 0
Views: 572
Reputation: 31
There is one new function for piecewise function in Symbolic Math Toolbox:piecewise
so
syms x
y = piecewise(-2<x<0,5*(1+x/2),0<x<2,5*(1-x/2),0);
fplot(y)
Upvotes: 1
Reputation: 1264
You need to select which values of x
to use for each condition as well. Something like this:
L = 4;
x = -5:0.1:5;
I = zeros(size(x));
cond1 = (-L/2)<x & x<0;
cond2 = 0<x & x<(L/2);
I(cond1) = 5*(1 + x(cond1)/(L/2));
I(cond2) = 5*(1 - x(cond2)/(L/2));
plot (x,I), grid
Not sure what you want to do which the boundry conditions x=0
, x=-2
and x=2
. But you just need to modify the cond1
and cond2
.
Upvotes: 1