CODEWITHSUNDEEP
httpgo
Mati Tucci
Mati Tucci

Reputation: 2976

Go http POST file

I'm really new in Go and I have to integrate Zamzar in a Go microservice. I need to POST a file and a data type (string).

Doing a curl looks like this:

curl https://sandbox.zamzar.com/v1/jobs \ -u user:pass \ -X POST \ -F "source_file=@/tmp/portrait.gif" \ -F "target_format=png"

This is what I have so far:

client := &http.Client{}

req, err := http.NewRequest("GET", "https://sandbox.zamzar.com/v1/jobs", nil)

req.SetBasicAuth("user", "pass")

resp, err := client.Do(req)

if err != nil {
  fmt.Printf("Error : %s", err)
} else {
  fmt.Println(resp)
}

How can I send the target_format as a string and source_file as a file? I already have the file ([]byte)

Upvotes: 2

Views: 1834

Answers (1)

Thundercat
Thundercat

Reputation: 120941

Use multipart.Writer to create the request body:

 var buf bytes.Buffer
 mpw := multipart.NewWriter(&buf)
 w, err := mpw.CreateFormFile("source_file", "portrait.gif")
 if err != nil {
    // handle error
 }
 if _, err := w.Write(imageBytes); err != nil {
    // handle error
 }
 if err := mpw.WriteField("target_format", "png"); err != nil {
   // handle error
 }
 if err := mpw.Close(); err != nil {
    // handle error
 }

 req, err := http.NewRequest("GET", "https://sandbox.zamzar.com/v1/jobs", &buf)
 req.Header.Set("Content-Type", mpw.FormDataContentType())

 ... continue as before.

Upvotes: 2

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