Reputation: 123
I'm currently learning how to build an application with pyqt5 and encountered some problem with closeEvent method, overriden so user gets asked for confirmation by QMessageBox object. It seems working well with X button - event gets 'accepted' when action is confirmed and 'canceled' when cancel button is clicked. However, when I use my Quit button from dropdown File menu, no matter which button I click, program gets closed with exit code 1. Seems strange, because I use same closeEvent method in both cases.
import sys
from PyQt5.QtWidgets import QApplication, QMessageBox, QMainWindow, QAction
class window(QMainWindow):
def __init__(self):
super().__init__()
def createUI(self):
self.setGeometry(500, 300, 700, 700)
self.setWindowTitle("window")
quit = QAction("Quit", self)
quit.triggered.connect(self.closeEvent)
menubar = self.menuBar()
fmenu = menubar.addMenu("File")
fmenu.addAction(quit)
def closeEvent(self, event):
close = QMessageBox()
close.setText("You sure?")
close.setStandardButtons(QMessageBox.Yes | QMessageBox.Cancel)
close = close.exec()
if close == QMessageBox.Yes:
event.accept()
else:
event.ignore()
main = QApplication(sys.argv)
window = window()
window.createUI()
window.show()
sys.exit(main.exec_())
Thanks for suggestions!
Upvotes: 11
Views: 53271
Reputation: 1
you need add this line is line to CreateUi your function
QMainWindow.closeEvent = self.closeEvent
Upvotes: 0
Reputation: 2345
If you want to close an PyQt5 app from a menu:
self.MainWindow.close()
(or what window do you want to closesys.exit(app.exec())
: self.MainWindow.closeEvent = lambda event:self.closeEvent(event)
def closeEvent(self,event):
method when you really want to close call event.accept()
(and perhaps return 1
) and if you don't want to close the window call event.ignore()
(not event.reject()
(it's not working for me))Upvotes: 1
Reputation: 11
def exit_window(self, event):
close = QtWidgets.QMessageBox.question(self,
"QUIT?",
"Are you sure want to STOP and EXIT?",
QtWidgets.QMessageBox.Yes | QtWidgets.QMessageBox.No)
if close == QtWidgets.QMessageBox.Yes:
# event.accept()
sys.exit()
else:
pass
Upvotes: 0
Reputation: 81
I had the same problem and fixed with a type-check-hack. It might be an ugly hack, but it works (tested on macOS 10.15 with python 3.8.0 and PyQt 5.14.2).
class Gui(QtWidgets.QMainWindow):
def __init__(self):
super(Gui, self).__init__()
uic.loadUi("gui.ui", self)
# ...
self.actionExit = self.findChild(QtWidgets.QAction, "actionExit")
self.actionExit.triggered.connect(self.closeEvent)
# ...
def closeEvent(self, event):
reply = QMessageBox.question(self, 'Quit?',
'Are you sure you want to quit?',
QMessageBox.Yes | QMessageBox.No, QMessageBox.No)
if reply == QMessageBox.Yes:
if not type(event) == bool:
event.accept()
else:
sys.exit()
else:
if not type(event) == bool:
event.ignore()
Upvotes: 3
Reputation: 91
The problem is accept is a method while ignore is just an attribute.
This code works for me:
def closeEvent(self, event):
close = QtWidgets.QMessageBox.question(self,
"QUIT",
"Are you sure want to stop process?",
QtWidgets.QMessageBox.Yes | QtWidgets.QMessageBox.No)
if close == QtWidgets.QMessageBox.Yes:
event.accept()
else:
event.ignore()
Upvotes: 9
Reputation: 142631
When you click button then program calls your function but with different event
object which doesn't have accept()
and ignore()
so you get error message and program ends with exit code 1.
You can assign self.close
and program will call closeEvent()
with correct event object.
quit.triggered.connect(self.close)
Upvotes: 10