CODEWITHSUNDEEP
powershellvariables
Kenneth Lui
Kenneth Lui

Reputation: 1

Powershell in variable assignment

i'm a newbie on powershell and i have come up with the problem in variable assignment:

Below is the script is used to retrieve free space percentage for drive with drivetype equal 3

I can't pass $line to line 6 by retrieving the value from the text file but if I do c: instead the script works perfectly, what's my mistake?

Get-WmiObject -Class Win32_logicalDisk | ? {$_.DriveType -eq '3'} | select deviceid > driveletter.txt

$content = Get-Content driveletter.txt | select-string ':' -simplematch

foreach ($line in $content)

   {

      "line $line"

      $freespace = Get-WmiObject -Class Win32_logicalDisk | ? {$_.DeviceID -eq '**$line**'}

      $drive = ($freeSpace.DeviceID).Split("=")

      "Your $drive Free Space Percentage is {0:P2}" -f ($freespace.FreeSpace / $freespace.Size)

   }

Upvotes: 0

Views: 472

Answers (1)

Sonny Puijk
Sonny Puijk

Reputation: 114

That can be done a little bit more efficiently i think

Get-WmiObject -Class Win32_logicalDisk | Where-Object {$_.DriveType -eq '3'} | ForEach-Object {Write-Host "Your $($_.DeviceID) Free Space Percentage is $($($_.FreeSpace) / $($_.Size))"}

The percentages now show up as 0.xx which isn't ideal. Still looking into that.

**Edit:**Your calculation was a bit off and also did some changes on the write host to make it more readable:

Get-WmiObject -Class Win32_logicalDisk | Where-Object {$_.DriveType -eq '3'} | ForEach-Object {Write-Host ('Your ' + $_.DeviceID + ' Free Space Percentage is ' +  ($_.FreeSpace / ($_.Size / 100)))}

Upvotes: 1

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