Reputation: 31
I am trying to customise an existing XSLT template by adding a default attribute value if it is missing. The original template is from 3rd party and better not to be touched. Below is the code to illustrate what I want to achieve. Any help will be greatly appreciated.
The sample xml file to be transformed:
<?xml version="1.0" encoding="UTF-8"?>
<images>
<image href="https://cityyearnh.files.wordpress.com/2011/02/boat.jpg" width="300" />
<image href="https://cityyearnh.files.wordpress.com/2011/02/boat.jpg"/>
</images>
Please note, there are 2 images in the xml file, one with @width attribute and one without. When @width is not defined, the XLST file below will not add a width attribute in the output html file.
The existing XSLT file
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html><body>
<h2>My Images</h2>
<xsl:apply-templates select="images/image" />
</body></html>
</xsl:template>
<xsl:template name="img_template" match="images/image">
<xsl:text> </xsl:text>
<img>
<xsl:apply-templates select="@href|@width" />
</img>
<br />
</xsl:template>
<xsl:template match="/images/image/@href">
<xsl:attribute name="src"><xsl:value-of select="." /></xsl:attribute>
</xsl:template>
<xsl:template match="/images/image/@width">
<xsl:attribute name="width"><xsl:value-of select="." /></xsl:attribute>
</xsl:template>
When @width is not defined, I want to add a width attribute of 50% in the output html file. I could modify the original img_template to achieve what I want, for example,
<xsl:template name="img_template" match="images/image">
<xsl:text> </xsl:text>
<img>
<xsl:apply-templates select="@href" />
<xsl:if test="@width">
<xsl:apply-templates select="@width" />
</xsl:if>
<xsl:if test="not(@width)">
<xsl:attribute name="width">50%</xsl:attribute>
</xsl:if>
</img>
<br />
</xsl:template>
However, it's not a good idea to modify the original template. Is there a way to call the original template and add some additional processing ?
I have tried to add an overriding template that calls the original and somehow add the default width attribute (but I do not know how). My code so far:
<xsl:template match="images/image">
<xsl:if test="@width">
<xsl:call-template name="img_template" />
</xsl:if>
<xsl:if test="not(@width)">
<p>Below image has no width attribute set. Add 50% width somehow ?</p>
<xsl:call-template name="img_template" />
</xsl:if>
</xsl:template>
Any help/suggestions will be greatly appreciated.
Upvotes: 1
Views: 1527
Reputation: 31
Following @MichaelKey's suggestion, I have worked out the following solution:
XSLT 2.0
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:include href="original.xsl" />
<xsl:template match="images/image[not(@width)]">
<xsl:variable name="old_content">
<xsl:call-template name="img_template" />
</xsl:variable>
<xsl:call-template name="re-generate">
<xsl:with-param name="oldcontent" select="$old_content"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="re-generate">
<xsl:param name="oldcontent" />
<img width="50%">
<xsl:copy-of select="$oldcontent/img/@*" />
</img>
<xsl:copy-of select="$oldcontent/*[not(self::img)]" />
</xsl:template>
</xsl:stylesheet>
In the above, I have assumed that the original template is in file original.xsl. Also, the first node generated by img_template is assumed to be the img. For more complex processing, it would be ideal to pass to a java function.
Upvotes: 0
Reputation: 163635
I've been dealing with a similar case recently where I was invoking a library stylesheet that put its output in a namespace, and I wanted it in no namespace. It would have meant overriding a lot of code. So instead I captured the output of the existing stylesheet in a variable, and transformed it.
Something like:
<xsl:template match="image">
<xsl:variable name="temp">
<xsl:apply-imports/>
</xsl:variable>
.. now process $temp e.g. to add missing attributes
</xsl:template>
Upvotes: 1
Reputation: 117165
it's not a good idea to modify the original template.
Why not? I would rewrite your stylesheet as:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/images">
<html>
<body>
<h2>My Images</h2>
<xsl:apply-templates select="image" />
</body>
</html>
</xsl:template>
<xsl:template match="image">
<img src="{@href}" width="50%">
<xsl:apply-templates select="@width" />
</img>
<br/>
</xsl:template>
<xsl:template match="@width">
<xsl:attribute name="width">
<xsl:value-of select="." />
</xsl:attribute>
</xsl:template>
</xsl:stylesheet>
This assigns a width
attribute with a default value of 50% to every image. If the image does have its own width
attribute, it will be used t overwrite the default value.
Alternatively, you could do:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/images">
<html>
<body>
<h2>My Images</h2>
<xsl:apply-templates select="image" />
</body>
</html>
</xsl:template>
<xsl:template match="image">
<img src="{@href}">
<xsl:attribute name="width">
<xsl:choose>
<xsl:when test="@width">
<xsl:value-of select="@width" />
</xsl:when>
<xsl:otherwise>50%</xsl:otherwise>
</xsl:choose>
</xsl:attribute>
</img>
<br/>
</xsl:template>
</xsl:stylesheet>
which is perhaps more verbose, but very clear.
Unfortunately, the original XSLT file is complex and comes as part of a software package. We do not suppose to modify any files there for maintenance reasons. Are there any ways to achieve what I want by using "overrides" ?
Yes, you could add the following template:
<xsl:template match="image[not(@width)]" priority="1">
<img src="{@href}" width="50%"/>
<br/>
</xsl:template>
Upvotes: 1