Reputation: 3126
I am new to websockets.
In my setup I have a trivial websocket server written in Go (playground)
I make a WebSocket
object, set up its onmessage
callback and call its send
method to test.
var w = new WebSocket("ws://localhost:12345/echo")
w.onmessage = (msg) => {
console.log(msg.data)
}
w.onopen = () => {
w.send("Hello") // this fires OK
}
What I expect to happen based on the server code is to receive the "Hello" message and to keep sending "yahoo" every 1.5s to the client. What actually happens is "Hello" is sent, but none of the "yahoo"'s make it thru. It seems somewhere along the WebSocket.readystate becomes 3 (CLOSED).
To clarify, the server receives and prints "Hello" then actually fires a "yahoo" message every 1.5s, but the connection is closed by then so the onmessage
callback never fires.
Am I missing or misunderstanding anything?
EDIT: Ran across comparison github.com/gorilla vs. golang.org/x/net, claims golang.org/x/net websocket implementation does not support pong. This may be the confirmation of it.
EDIT: Package golang.org/x/net/websocket closes the websocket connection when the handler ServeHTTP function returns. By default a websocket connection is tied to an instance of the handler.
Upvotes: 1
Views: 4583
Reputation: 5500
When the handler function returns, in your case EchoServer
the socket will be automatically closed by the http framework.
Since you start a go routine for the loop writing the yahoo
response to the client the EchoServer
function will terminate (and therefor closing the socket) before it has time to send a response.
The solution is to remove the spawning of the go routine and just do the loop inside the EchoServer
.
Upvotes: 1