CODEWITHSUNDEEP
java
Aishu
Aishu

Reputation: 1320

Printing character in java

I'm trying print a given String char by char:

public static void main(String[] args) {
    char c;
    Scanner scaner = new Scanner(System.in);
    int length = scaner.next().length();
    System.out.println(length);
    int i = 0;

    while (i < length) {
        c = scaner.next().charAt(i);
        System.out.println(c);
        i++;
    }
}

Once this code has reached int length = scaner.next().length(); it doesn't continue. What's causing this?

Upvotes: 1

Views: 108

Answers (2)

Nordiii
Nordiii

Reputation: 466

You need to enter something after calling next().

As addition too Alexander's answer.

The line: int length = scaner.next().length(); gets the next line and then checks the length. So you already got the next line and calling next() again asks for different input.

That's the reason why you should always store the return value of next() in a variable!

Upvotes: 1

Alexander Pogrebnyak
Alexander Pogrebnyak

Reputation: 45576

You should store the scanned value in the temporary variable.

char c;
Scanner scaner = new Scanner(System.in);

// Storing scanned value
String nextStr = scaner.next();

int length = nextStr.length();
System.out.println(length);

int i = 0;
while(i < length){
    c = nextStr.charAt(i);
    System.out.println(c);
    i++;
}

In your original code you call next repeatedly in a loop, but this does not return the original scanned value, but the next line of input.

Upvotes: 4

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