CODEWITHSUNDEEP
javascriptnode.jsloops
dmx
dmx

Reputation: 1990

Loop and return value with q

I am trying to find the best way to loop through an array, perform an operation on every element of the array and return the result using Q.

Let's say I have this array:

var q = require('q');
var arr = [1, '2', "3", "undefined", undefined];
var values = [];

q.fcall(
   function(){
     arr.forEach(d){
        if (d){
           values.push(1);
        }
        else{
          values.push(0);
        }
     }
     return values;
   }
 ).then(
  function(v){
    v.forEach(d){
    console.log(d);
  }
 });

Upvotes: 1

Views: 90

Answers (1)

vesse
vesse

Reputation: 5078

If the operation you perform is not asynchronous you can just use regular Array#map and resolve the mapped array:

var operationFunction = function(d) {
  return d ? 1 : 0;
};

q(arr.map(operationFunction)).then(function(v) {
  v.forEach(function(d) {
    console.log(d);
  });
});

If your operation is a node.js style asynchronous function you can map the source array to an array of promises, and then wait for them to resolve:

var operationFunction = function(d, done) {
  process.nextTick(function() {
    done(null, d ? 1 : 0);
  });
};

var wrapperFunction = function(d) {
  return q.nfcall(operationFunction, d);
};

q.all(arr.map(wrapperFunction)).then(function(v) {
  v.forEach(function(d) {
    console.log(d);
  });
});

Or, if the operation function is asynchronous and you can edit it you could use deferred objects:

var operationFunction = function(d) {
  var deferred = q.defer();
  process.nextTick(function() {
    deferred.resolve(d ? 1 : 0);
  });
  return deferred.promise;
};

q.all(arr.map(operationFunction)).then(function(v) {
  v.forEach(function(d) {
    console.log(d);
  });
});

Upvotes: 1

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