CODEWITHSUNDEEP
phpimage-processingimagick
kaese
kaese

Reputation: 10599

Get/set DPI with PHP GD/Imagick?

I'm building a Web application that will handle image files that will ultimately be printed, large format.

As part of this, I need to get (i.e. read) and set (i.e. change) the DPI of an image file.

Is this possible through PHP GD or PHP Imagick?

Thanks,

BK

Edit:

The DPI of a image can be accessed through iMagick's getImageResolution method:

public function getDPI() {

    $imgDPI = $this->image->getImageResolution();
    return $imgDPI;

}

and the DPI of an image can be set through iMagick's setImageResolution method:

public function setDPI($DPIX, $DPIY) {

    $this->image->setImageResolution($DPIX,$DPIY);

}

Upvotes: 15

Views: 12293

Answers (3)

Felipe Marques
Felipe Marques

Reputation: 131

This is my work solution at Joox.io

/**
 * @param $filename
 * @return array
 */
function getImageDPI($filename)
{
    $resolutions = null;

    if (class_exists('Imagick')) {

        $image = new Imagick($filename);
        $resolutions = $image->getImageResolution();

    } else {

        $a = fopen($filename, 'r');
        $string = fread($a, 20);
        fclose($a);

        $data = bin2hex(substr($string, 14, 4));
        $x = substr($data, 0, 4);
        $y = substr($data, 4, 4);

        $resolutions = array('x' => hexdec($x), 'y' => hexdec($y));

    }

    return $resolutions;
}

Upvotes: -1

Vladimir Miroshnichenko
Vladimir Miroshnichenko

Reputation: 1295

in order to use "getImageResolution();" you must be sure that resolution in "PixelsPerInch"...sometimes it can be "PixelsPerCentimeter"

use following code to get image info:

$imagick = new Imagick($filename);
$data = $imagick->identifyimage();
var_dump($data);

result (when PixelsPerInch):

array(11) {
              ["imageName"]=> string(11) "/jpg300.jpg"
              ["format"]=> string(51) "JPEG (Joint Photographic Experts Group JFIF format)"
              ["units"]=> string(13) "PixelsPerInch"
              ["type"]=> string(9) "TrueColor"
              ["colorSpace"]=> string(3) "RGB"
              ["compression"] => string(4) "JPEG"
              ["fileSize"] => string(6) "8.72mb"
              ["mimetype"] => string(10) "image/jpeg"
              ["geometry"] => array(2) {
                        ["width"]  => int(11812)
                        ["height"] => int(7876)
              }
              ["resolution"]=> array(2) {
                    ["x"]=> float(300)
                    ["y"]=> float(300)
              }
              ["signature"]=> string(64) "7fc387ea465ec716e9fd6e233bb1d3740cb509f5667ed2a4df0199e6e664590e"
            }

or (when PixelsPerCentimeter):

    array(11) {
      ["imageName"]=> string(8) "/psm.jpg"
      ["format"]=> string(51) "JPEG (Joint Photographic Experts Group JFIF format)"
      ["units"]=> string(19) "PixelsPerCentimeter"
      ["type"]=> string(9) "TrueColor"
      ["colorSpace"]=> string(3) "RGB"
      ["compression"]=> string(4) "JPEG"
      ["fileSize"]=> string(7) "25.01mb"
      ["mimetype"]=> string(10) "image/jpeg"
      ["geometry"]=>
      array(2) {
        ["width"]=> int(11812)
        ["height"]=> int(7876)
      }
      ["resolution"]=>
      array(2) {
        ["x"]=> float(118.11)
        ["y"]=> float(118.11)
      }
      ["signature"]=> string(64) "b491e059624e79a4dee62d9cc7646019927b2222bfed9ac8dd4342185e648eaf"
    }

Upvotes: 4

Pekka
Pekka

Reputation: 449525

In a primitive bitmap format like those that GD outputs, the dpi setting is merely a meta information that the processing application can use to convert the pixel size into a physical unit.

As far as I know, it is not possible to manipulate metadata directly in GD. You'd have to use an external library for that.

That said, I don't think it is really necessary. Just generate the image in whatever pixel dimensions you need (the number of pixels is the really relevant information!), and tell the printing process what dpi setting to use.

Upvotes: 2

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