Reputation: 13
I am fetching and looping on strings which can have one brackets or multiple as shown below. I want the strings inside the last bracket.
strOne = "This contains (18xp) (23lo) (SerialA)"
strTwo = "This contains (jxp) (SerialB)"
strThree = "Some strings (randomA9)"
I tried to use below code but it only capture first:
regFormat = '(\([A-Z0-9]+\))'
pathReg = re.compile(regFormat)
findr = re.findall(pathReg , strOne)
print(findr)
RESULT : ['(18xp)']
Upvotes: 0
Views: 43
Reputation: 1112
You have to use a regexp signs indicating the start and the end of the line.
Try:
'^.*?(\([A-Z0-9]+\))$'
Upvotes: 1