CODEWITHSUNDEEP
pythonpython-2.7python-3.xlogging
Pu Ba Abhijit
Pu Ba Abhijit

Reputation: 41

How to create new custom logger function in Python

I want to create new custom logger function. we have default functions available like below 

    logger.debug('debug message')
    logger.info('info message')
    logger.warn('warn message')
    logger.error('error message')
    logger.critical('critical message')

How can create a new custom logger function using custom code. custom logger like below example -

logger.success('success message')

Upvotes: 4

Views: 3144

Answers (1)

Vasili Syrakis
Vasili Syrakis

Reputation: 9601

Given that the current logging library doesn't really cater for this, the only way I can conceive that you'd be able to achieve what you are asking is to make a subclass of the logging.Logger class and define your own success method.

For example:

import logging

SUCCESS = 5
logging.addLevelName(5, 'SUCCESS')


class Logger(logging.Logger):
    super(logging.Logger)

    def success(self, msg, *args, **kwargs):
        if self.isEnabledFor(SUCCESS):
            self._log(SUCCESS, msg, args, **kwargs)


formatter = logging.Formatter('%(levelname)s - %(name)s - %(message)s')
ch = logging.StreamHandler()
ch.setFormatter(formatter)

log = Logger('mycustomlogger')
log.setLevel(SUCCESS)
log.addHandler(ch)

log.success('Hello World')

Upvotes: 3

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