CODEWITHSUNDEEP
assemblyx86-16tasm
Liad BR
Liad BR

Reputation: 33

Printing half sentence in 8086 assembly

I've written this code and for some reason it only prints part of the sentence and it also doesn't assign the number from DL to the string and prints a 'heart' instead.

I checked in TurboDebugger and everything, beside that part, went perfectly.

I add the relevant parts: 

.MODEL SMALL
.STACK 100h
.DATA
  ARR1   DW 333,20989,3456,2082
  ARR2   DW 333,15,5436,2082
  ARR3   DW ?
  ANSWER DB 'The last digit is: X',13,10,'$'
  TEN    DW 10
.CODE
    MOV AX,@DATA   ; DS can be written to only through a register
    MOV DS,AX      ; Set DS to point to data segment
  MAX:
    CMP AX,10
    ;MAX<10
    JL LESSTHAN10
    ;MAX>10
    MOV DX,0
    DIV TEN
    MOV ANSWER[19],DL
    JMP PRINTANSWER
  PRINTANSWER:
    MOV AH,9               ; Set print option for int 21h
    MOV DX,OFFSET ANSWER   ;  Set  DS:DX to point to answerString
    INT 21h                ;  Print DisplayString

Here is a screenshot of my attempt of assembling this:

screen print

Upvotes: 1

Views: 514

Answers (1)

Fifoernik
Fifoernik

Reputation: 9899

for some reason it only prints part of the sentence

This happens because you are overwriting the first 6 characters from your message ANSWER when you write something in the array ARR3.
Make sure to provide enough space for this 3rd array by writing:

ARR3   DW 4 dup (?)
ANSWER DB 'The last digit is: X',13,10,'$'

it also doesn't assign the number from DL to the string and prints a 'heart' instead.

The remainder from the division by 10 gave a number from 0 to 9 that you want to print as a character. You need to actually turn it into a character first. This is done by adding 48 to it. An elegant way of doing this is by writing add dl, "0".

DIV TEN
add dl, "0"
MOV ANSWER[19],DL

Upvotes: 2

Related Questions