CODEWITHSUNDEEP
javaarraysstringlettersfind-occurrences
Gatekeeper15
Gatekeeper15

Reputation: 3

java - Count letter occurrences in strings into int array of 26

I need to take multiple lines of text and count the occurrences of each letter in every line. The last line must end in a period. I'm asked to make an int array of length 26 where arrayName[0] = number of a's, arrayName[1] = number of b's, etc and that letter case needs to be ignored. I'm having trouble checking the occurrences of each letter and defining the indexed variables with the correct number of occurrences. My code so far:

import java.util.Scanner;

public class LetterCounter 
{
public static void main(String[] args)
{
    Scanner input = new Scanner(System.in);

    String[] textBlock = new String[10];

    System.out.println("Enter text.");
    int index;
    //Allows me to type in something for all "lines" of text until I end one with a period.
    for(index = 0; index < textBlock.length; index++)
    {
        textBlock[index] = input.nextLine();

        if(textBlock[index].contains("."))
        {
            System.out.println("Period found");
            break;
        }
    }
    //Outputs what the user printed except for the lines not typed in (they return null).
    System.out.println("Text input by user:");
    for(index = 0; index < textBlock.length; index++)
    {
        if(textBlock[index] != null)
        {
            System.out.println(textBlock[index]);
        }
    }
    //int array
    int[] occurrences = new int[26];

    //used to turn letter into number
    char letter = 'a' - 49;
    char letter2 = 'b' - 49;
    char letter3 = 'c' - 49;

    //checks that numbers are correct (return "0" for a, "1" for b, and "2" for c)
    System.out.println("Number value of a: " + letter);
    System.out.println("Number value of b: " + letter2);
    System.out.println("Number value of c: " + letter3);

}// End of main
}//End of program

Upvotes: 0

Views: 3870

Answers (3)

rimonmostafiz
rimonmostafiz

Reputation: 1471

Count the character occurrence of every line. and just print them. try this...

//final int SIZE = 1000;
//String[] textBlock = new String[SIZE];

Scanner in = new Scanner(System.in);
String line;

//frequency array for storing which Character is occurs how many times
int[] frequencyArray = new int[26];
Arrays.fill(frequencyArray, 0);

System.out.println("Enter text : ");

// take input un-till find the (.) in a line
// and also count the frequency of Character of current line
while (true) {
    line = in.nextLine();
    for (int i = 0; i < line.length(); i++) {
        char ch = Character.toLowerCase(line.charAt(i));
        if (Character.isLetter(ch)) {
            frequencyArray[ch - 'a']++;
        }
    }
    if (line.contains(".")) {
        break;
    }
}

for (int i = 0; i < 26; i++) {
    System.out.println("Total Number of " + (char)(i + 'a') + " : " + frequencyArray[i]);
}

Upvotes: 2

Bohemian
Bohemian

Reputation: 425258

If you don't print debug messages, you can do the work with only 1 line:

System.out.println("Enter lines of text (period to end):");
new Scanner(System.in).useDelimiter("\\.").next().chars()
  .filter(i -> i >= 'a' && i <= 'c').boxed()
  .collect(Collectors.groupingBy(i -> i, Collectors.counting())
  .forEach((c, n) -> System.out.format("Number value of %s: %d\n", (char)c, n));

Upvotes: 0

Ajaykumar
Ajaykumar

Reputation: 416

Declare the array outside your loop and increment the count of that array when the character mathes

Declare this inside the loop

int intialCount = occurrences(charAt(textBlock[index])-49);
occurrences(charAt(textBlock[index])-49) = intialCount++;

You will find occurences of 'a' in occurences[0] which will return a count.

Upvotes: 0

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