Reputation: 4841
I have a list of spans with particular class "place" and some of them have class "activated". Is there a way to select the first item with class "activated" and the last?
<span class="place" onclick="activate();">1</span>
<span class="place" onclick="activate();">2</span>
<span class="place activated" onclick="activate()">3</span>
<span class="place activated" onclick="activate();">4</span>
<span class="place activated" onclick="activate();">5</span>
<span class="place activated" onclick="activate();">6</span>
<span class="place" onclick="activate();">7</span>
Upvotes: 28
Views: 39082
Reputation: 106037
var places = $('span.place.activated');
var first = places.first(),
last = places.last();
Explanation: The span.places.activated
selector will get all <span>
s with both "place" and "activated" classes. Then the first()
and last()
methods will return the first and last items of that set. This is preferable to using the :first
and :last
pseudoselectors because selection is expensive and this way we only do selection once and then rely on (cheap) array operations to get the first and last elements.
Upvotes: 14
Reputation: 1423
If you take care about performance, than better use $('span.place.activated')
instead $('.activated:first')
.
But, in this case, the second variant correct too.
Upvotes: 1
Reputation: 18964
var firstspan = $('span.activated:first'),
lastspan = $('span.activated:last');
By the way, if you're using jQuery, what's with all the inline click events?
You could add some code like so:
$('span.place').click(function() {
activate(); // you can add `this` as a parameter
// to activate if you need scope.
});
Upvotes: 39
Reputation: 4315
var first = $('.activated:first');
var last = $('.activated:last');
Upvotes: 0