CODEWITHSUNDEEP
c++cstructtypedef
user472875
user472875

Reputation: 3175

struct and typedef in C versus C++

I am currently using a C++ IDE for something that will need to work on C, and wanted to make sure that I won't have problems with this later on. After making the struct below:

typedef struct test {
   int a;
   int b;
};

I then create an instance of it using test my_test; then stuff like my_test.a = 5, etc... and this works fine in my VStudio C++. Is this going to work on gcc later on?

I read the related questions that popped up (I see I am not the first person with this kind of question, either) but no one seemed to use the way I did.

In fact, what is the difference between typedef struct {//stuff} test; and my version?

Upvotes: 10

Views: 5065

Answers (3)

Benjamin Lindley
Benjamin Lindley

Reputation: 103693

typedef struct THIS_IS_A_TAG
{
    int a;
    int b;
} THIS_IS_A_TYPEDEF;

THIS_IS_A_TYPEDEF object1;     // declare an object.       C:Ok,     C++:Ok
struct THIS_IS_A_TAG object2;  // declare another object.  C:Ok,     C++:Ok
THIS_IS_A_TAG object3;         // declare another object.  C:Not Ok, C++:Ok

The reason for the typedef is because C programmers would like to be able to do that third thing, but they can't.

Upvotes: 22

Jonathan Leffler
Jonathan Leffler

Reputation: 753525

In both C and C++, the example construct is modestly pointless:

typedef struct test {
   int a;
   int b;
};

In C, this says there is a type struct test with the two integers as content. If there was a name between the close brace '}' and the semi-colon ';', then you would get some benefit from the keyword typedef; as it stands, the keyword typedef is redundant, and (if set fussy enough), GCC will warn you about it.

In C++, this says there is a type struct test; further, in C++, it creates a type test too (which does not happen in C). The keyword typedef can still be left out and the same result will be achieved.

The syntax is legal; it is not useful, that's all. The keyword typedef can be omitted without changing the program's meaning in the slightest.

You can do:

typedef struct test {
   int a;
   int b;
} test;

Now, in both C and C++, you have a type struct test and an alias for it test.

Upvotes: 8

Michael Aaron Safyan
Michael Aaron Safyan

Reputation: 95479

The difference between:

struct Name {};

And

typedef struct Name {} Name;

Is that, in C, you need to use:

struct Name instance_name;

With the former, whereas with the latter you may do:

Name instance_name;

In C++, it is not necessary to repeat the struct keyword in either case. Note that your example in which you create a typedef with no name (i.e. typedef struct Name{};) is non-standard AFAIK (if you use the keyword typedef, then you need to supply an alias to which to typedef that name).

As for the last variation:

typedef struct { /* ... */ } Name;

The code above creates an unnamed struct that is aliased to Name. You would use such a struct just the same way you would with typedef struct Name { /* ... */ } Name;, however compilers often emit the name of the struct (not the alias), and so you may get better error messages involving the struct if you give it a name and typedef that as opposed to typedef'ing an anonymous struct.

Upvotes: 19

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