CODEWITHSUNDEEP
javamultithreadingsockets
anonimosz
anonimosz

Reputation: 7

number format Exception for input string to integer

I am trying to receive message using socket
When Executing this code i am getting NumberFormatException

public class ThreadSocket extends Thread {
    Socket socket;
    int k;

    ThreadSocket(Socket socket) {
        this.socket = socket;
    }

    public void run() {
        try {
            String message = null;
            BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(socket.getInputStream()));
            while ((message = bufferedReader.readLine()) != null) {
                System.out.println("Incomming message client : " + message);
                k += Integer.parseInt(message);
                System.out.println("la somme est :" + k);
            }
            socket.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

This Exception : 

Exception in thread "Thread-0" java.lang.NumberFormatException: For input string: "3 : 2"
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    at java.lang.Integer.parseInt(Integer.java:580)
    at java.lang.Integer.parseInt(Integer.java:615)
    at ThreadSocket.run(ThreadSocket.java:33)

Upvotes: 0

Views: 870

Answers (2)

Anonymous
Anonymous

Reputation: 86276

I am still not quite sure what the possible messages received on the socket are. The following will accept messages on the form client : number as well as messages containing only the number. Decide if this is what you need.

        while ((message = bufferedReader.readLine()) != null) {
            System.out.println("Incomming message client : " + message);
            // is there a colon followed by a space in the message?
            final String delimiter = ": ";
            int indexOfColon = message.lastIndexOf(delimiter);
            if (indexOfColon == -1) { // no, no colon and space in message
                // try to use entire message
                k += Integer.parseInt(message);
            } else { // yes
                // take out the part after the colon and space and try parsing it as an integer
                int number = Integer.parseInt(message.substring(indexOfColon + delimiter.length()));
                k += number;
            }
            System.out.println("la somme est :" + k);
        }

Upvotes: 1

user7217438
user7217438

Reputation: 1

You have to cast the numbers of your input String one by one. and Then you can divide them.

Upvotes: 0

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