CODEWITHSUNDEEP
javamultithreadingconcurrencythread-safety
Wulf
Wulf

Reputation: 323

Concurrency: Changing a variable with unsynchronized methods

Take this ConcurrentDouble class definition as an example:

public class ConcurrentDouble {

  public double num = 0;

  public void subtract(double num) { 
    this.num -= num; 
  }

  public void add(double num) { 
    this.num += num; 
  }
}

Now if I did the following,

public class Test {
  public static void main(String[] args) {
    ConcurrentDouble d1 = new ConcurrentDouble();

    Thread one = new Thread(() -> { d1.add(5); }).start();
    Thread two = new Thread(() -> { d1.subtract(5); }).start();

    one.join();
    two.join();

    System.out.println(d1.num); // <-- OUTPUT
  }
}

We know the number starts off at 0, and we expect it to have 0 at the end. Is it possible that the number becomes -5.0 or 5.0?

Upvotes: 0

Views: 72

Answers (1)

JB Nizet
JB Nizet

Reputation: 692181

Yes, it's possible. -= and += are not atomic operations. And even then, the JVM doesn't guarantee that a write to a double is atomic.

Upvotes: 3

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