Reputation: 47
Want to know why that function doesn't work ?
students = {'dsd': 13}
student1 = {'dsdsd': 15}
print(students.update(student1))
After printing it just brings out None
in console.
Upvotes: 3
Views: 4862
Reputation: 2145
The update
method merges the dict
s in-place and returns 'None', which is what you're printing. You need to print students
itself.
students = {'dsd': 13}
student1 = {'dsdsd': 15}
students.update(student1)
print(students)
Upvotes: 4
Reputation: 48067
Because dict1.update(dict2)
update the value of dict1
with the values of dict2
but do not returns anything (hence printing None
in your case). In order to see the updated values, you need to do:
students.update(student1)
print(students)
As a reference, check dict.update()
document which says:
Update the dictionary with the key/value pairs from other, overwriting existing keys. Return
None
.
Upvotes: 6