Reputation: 197
I have a 'billing' table which represent all instances of billings from my subscribers. A subscriber can have multiple billings.
I have a simple SQL request which is :
SELECT count(billing_id),subscriber_id
FROM billing
group by subscriber_id
As a result I have a list of all my subscribers with the number of billings they've made. I want to have a list of all the billings no grouped by subscribers, but I want the result of the previous request appearing in each lines.
Example: Result of my previous request:
sub_id nb_billings
1 3
2 2
What I want :
sub_id nb_billings
1 3
1 3
1 3
2 2
2 2
Thanks
Upvotes: 1
Views: 74
Reputation: 5135
I guess this should suffice :
SELECT s.subscriber_id,
s.billing_id,
s.TotalCount
FROM (
SELECT subscriber_id,
billing_id,
COUNT(billing_id) AS TotalCount
FROM BILLING
GROUP BY subscriber_id,
billing_id
) s
GROUP BY s.subscriber_id,
s.TotalCount,
s.billing_id
ORDER BY s.subscriber_id
This should give you the result as follows :
subscriber_id billing_id TotalCount
1 10a 2
1 10b 2
1 10c 1
2 10a 1
2 10b 1
2 10c 3
2 10d 1
You can see this here -> http://rextester.com/AVVS23801
Hope this helps!!
Upvotes: 1
Reputation: 8113
I'd do it like this;
SELECT
b.subscriber_id
,a.billing_count
FROM billing b
JOIN (SELECT subscriber_id, count(billing_id) billing_count FROM billing GROUP BY subscriber_id) a
ON b.subscriber_id = a.subscriber_id
The subquery works out the count of billing_id by subscriber, this is then joined to all rows of your original table (using subscriber_id). This should give the result you're after.
Upvotes: 1
Reputation: 2071
select subscriber_id,count(billing_id)over(partition by subscriber_id)
from billing
will do just that.
Upvotes: -1
Reputation: 12378
You can use a subquery to do that:
SELECT
(SELECT count(t2.billing_id) FROM billing t2 WHERE t2.subscriber_id = t1.subscriber_id),
t1.subscriber_id
FROM billing t1
Upvotes: 1