Reputation: 1532
Heres my current code in php with one parameter which works
<?php
$sid = "012";
echo '<input type="button" value="Submit" onclick="changeConfirmed('.$sid.')">';
?>
Now im trying to pass two parameters or more, but cant seem to get it to work, here is my attempt:
<?php
$name="abc
$sid = "012";
echo '<input type="button" value="Submit" onclick="changeConfirmed('.$sid.','.$name.')">';
?>
Upvotes: 0
Views: 78
Reputation: 138
If one of your JavaScript function parameters is a string, you'll have to correctly enclose it in quotes:
<?php
$name="abc";
$sid = "012";
echo '<input type="button" value="Submit" onclick="changeConfirmed('.$sid.',\''.$name.'\')">';
?>
You get away with $sid not enclosed in quotes because it looks like a number.
Upvotes: 2
Reputation: 744
You need quotes around the parameters or javascript treats them like variables instead of strings.
echo '<input type="button" value="Submit" onclick="changeConfirmed(\''.$sid.'\',\''.$name.'\')">';
Upvotes: 3