CODEWITHSUNDEEP
c
David Ramos
David Ramos

Reputation: 31

Abort trap 6 error in C - mac terminal

I'm learning C and recently I was trying some tutorials from youtube, and I was running this code, but it doesnt work I don't know why... when i run it on Terminal, gives an error "Abort trap: 6"

I was following this tutorial : https://youtu.be/7F-Q2oVBYKk?list=PL6gx4Cwl9DGAKIXv8Yr6nhGJ9Vlcjyymq

#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int main ()
{
  char name[15] = "John Snow";
  printf("My name is %s\n", name);

  name[2] = 'z';                   
  printf("My name is %s\n", name);

  char food[] ="pizza";
  printf("The best food is %s \n", food);

  strcpy(food, "bacon");
  printf("The best food is %s \n", food);

  return 0;
}

Upvotes: 3

Views: 18027

Answers (1)

Sachin Patney
Sachin Patney

Reputation: 129

The error means you are writing to memory you don't own. Will likely happen if you try to copy a string longer than the one you specified for food ('pizza'). In this case it could be cos you are copying the string into memory location assigned to a string constant.

try this instead:- 

char *food = malloc(sizeof(char)*6); 
strcpy(food, "pizza"); 
printf("The best food is %s \n", food); 

strcpy(food, "bacon");`
printf("The best food is %s \n", food);

Upvotes: 4

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