CODEWITHSUNDEEP
php
BSNSENAN
BSNSENAN

Reputation: 27

I got Error Notice: Array to string conversion in my code php

hi guys i got problem in my code i don't know where come form this my code 

<h1><?php echo $item["title"]; ?> </h1>
       <table>
          <tr>
             <th>Catageory</th>
             <td><?php echo $item["category"]; ?></td>
         </tr> 
         <tr>
             <th>Genre</th>
             <td><?php echo $item["genre"]; ?></td>
         </tr> 
         <tr>
             <th>Format</th>
             <td><?php echo $item["format"]; ?></td>
         </tr> 
         <tr>
             <th>Year</th>
             <td><?php echo $item["year"]; ?></td>
         </tr> 
         <?php
         if(strtolower($item["category"]) == "books"){
             ?>
        <tr>
             <th>Authors</th>
             <td><?php echo $item["authors"]; ?></td>
         </tr> 

        <tr>
             <th>Publisher</th>
             <td><?php echo $item["publisher"]; ?></td>
         </tr> 
        <tr>
             <th>ISBN</th>
             <td><?php echo $item["isbn"]; ?></td>
         </tr>           

    <?php    }  ?>

And the error message,

and Iam sure all code are same i don't what's problem !!

Upvotes: 0

Views: 6847

Answers (3)

BSNSENAN
BSNSENAN

Reputation: 27

my problem is solved

by replace 

             <td><?php echo $item["authors"]; ?></td>

to

<td><?php echo implode(",", $item["authors"]); ?></td>

Upvotes: 1

Naga
Naga

Reputation: 2168

You are trying to echo an array variable which is not right. Use the below debug code and you have to parse the array however you want.

    Authors ->  <?php echo "<pre>";print_r($item["authors"]);echo "<pre>"; ?>

Upvotes: 1

Rizban Ahmad
Rizban Ahmad

Reputation: 139

enter image description here

As per your image, you are trying to print string on line 58, but you are getting array from your resultant query. So try to var_dump($yourvar) and check that are you getting required string or an array

Upvotes: 1

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